Question

Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.

Answer 1

Moving at 1.2 m/s inside the opposite direction following the collision.

Define collision.

A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

The law of momentum conservation can be used to calculate Miguel's post-collision velocity.

Mass times velocity equals momentum, that is a vector quantity (p=mv). Well before collision, the system's momentum.
Miguel and Fernando's car—was equal to 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s). Just after collision,
The system's momentum is equal to 782 kg*m/s (m1=72 kg) (v1=? m/s) + (m2=125 kg) (v2=2 m/s).
We can calculate Miguel's post-collision velocity to be -1.2 m/s by solving for v1.
Miguel is therefore moving at 1.2 m/s inside the opposite direction following the collision.

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