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masha68 [24]
4 years ago
9

If a single-load Series circuit has one 20 Ohm bulb, and a

Physics
1 answer:
Alex Ar [27]4 years ago
5 0

At the instant the second bulb is connected ...

... the brightness of the <u>first bulb</u> doesn't change

... the brightness of the <u>second bulb</u> changes from dark (no brightness) to equal to the first bulb

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An organ pipe is open at both ends. It is producing sound
ozzi

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

\lambda = \frac{2}{3}L

Here,

\lambda = Wavelength

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

\lambda = \frac{v}{f}

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore

\lambda = \frac{343}{262}

\lambda = 1.3091m

Finally the length of the pipe would be

L= \frac{3}{2}(1.3091)

L = 1.963m

3 0
3 years ago
The free-fall acceleration on Mars is 3.7 m/s2.
hichkok12 [17]

Answer:

(a) The length of the pendulum on Earth is 36.8cm

(b) The length of the pendulum on Mars is 13.5cm

(c) Mass suspended from the spring on Earth is 0.37kg

(d) Mass suspended from the spring on Mars is 0.36kg

Explanation:

Period = 1.2s, free fall acceleration on Earth = 9.8m/s^2, free fall acceleration on Mars = 3.7m/s^2

( a) Length of pendulum on Earth = [( period ÷ 2π)^2] × acceleration = (1.2 ÷ 2×3.142)^2 × 9.8 = 0.0365×9.8 = 0.358m = 35.8cm

(b) Length of the pendulum on Mars = (1.2÷2×3.142)^2 × 3.7 = 0.0365×3.7 = 0.135cm = 13.5m

(c) Mass suspended from the spring on Earth = (force constant×length in meter) ÷ acceleration = (10×0.358) ÷ 9.8 = 0.37kg

(d) Mass suspended from the spring on Mars = (10×0.135)÷3.7 = 0.36kg

6 0
3 years ago
A 15.0-kilogram mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the
Mars2501 [29]
The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
7 0
4 years ago
Celina has a water sample that's contaminated with salt and microorganisms. Which method should she use to purify the water.
sergiy2304 [10]
She should filter the water with carbon and oxygen
7 0
3 years ago
Read 2 more answers
Kilo-  -  1,000<br>deka-  -  10<br><br>How much larger is a kilo- than a deka-?
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lets's \ take \ an \ example \ one \ gram: \\ \\ 0,001kg \\ \\ 0,01hg \\ \\ 0,1dag \\ \\ \boxed{1g} \\ \\ 10dg \\ \\ 100cg \\ \\ 1000mg  \\ \\ the \ units \ are \ rising \ and \ decreasing \ from \ 10 \ to \ 10 \ results \ \\ \\ a \ kilogram \ is \ 100 \ times \ larger \ than \ a \ dekagram
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3 years ago
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