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antoniya [11.8K]
3 years ago
10

The least penetrating form of radiation is ____. a. beta radiation c. alpha radiation b. gamma radiation d. X rays

Physics
2 answers:
svet-max [94.6K]3 years ago
8 0
C) alpha radiation seems to be the answer

professor190 [17]3 years ago
5 0

Answer:

The correct answer is option (C) Alpha radiation

Explanation:

The types of radiation which are alpha, beta and gamma radiation have different penetration power.

Penetration power is the ability of each of the types of radiation to pass through matter. The more they penetrate, the more dangerous they will be.

Alpha has the least penetration power because it has large mass size

Gamma has the highest penetration power because it has no mass size

Beta has the medium penetration power because it has a small mass size

Therefore, the penetration power is affected by the size of mass they carry.

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which statement best describes how changes behave a.opposites charges repel against each other and like charges attract to each
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a wave travels at a speed of 793 m/s and has a wavelength of 2.3 meters. calculate the frequency of the wave​
Savatey [412]

Answer:

344.8 Hz

Explanation:

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the speed of the wave

\lambda is its wavelength

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v = 793 m/s

\lambda=2.3 m

Substituting into the equation, we find

f=\frac{793 m/s}{2.3 m}=344.8 Hz

4 0
3 years ago
Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each mo
postnew [5]

Answer:

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

from the principle of momentum

In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

momentum before collision=momentum after collision

mass, m

u=initial velocity of the identical masses

v2=the common velocity after the collision

Note that the collision is inelastic , since they both moved with the same velocity

umcosφ+umcosφ=(m+m)v2cos−θ2

2mucosφ=2mv2cos−θ2

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

8 0
3 years ago
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