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iVinArrow [24]
10 months ago
10

answer questions1) The south pole of the steel magnet will be brought closer to the iron nail head. Which pole will be at the po

inted end of the nail?2) When the magnet is in the form of a horseshoe, an iron object, such as a nail, is attracted to one end of a pole and the other end to the other. Why?3) Explain why two wires carrying an electric current in the same direction attract each other.
Physics
1 answer:
Anvisha [2.4K]10 months ago
8 0
Answer:

North pole

Explanation:

According to the law of magnetism:

<em>Unlike poles attract while like poles repel</em>

Since the south pole of the steel is brought near the nail, and the nail is meant to attract the steel magnet, the nail domain realigns itself to produce a pole opposite to the pole of the steel magnet brought near it.

Since the North pole is the opposite of the south pole, the North pole will be at the pointed end of the nail so that it can attract the steel magnet.

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If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?
Alex

Answer:

0.015 m/s2

Explanation:

Using Newtons 2nd law.

F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.

So substitute the values in SI units.

m = \frac{3}{1000} kg

Therefore F = 0.003×5 = 0.015 m/s2

3 0
2 years ago
A wind instrument that produces only odd-numbered standing wave modes has what configuration of its ends?
Luda [366]

Answer:

Open- closed

Explanation:

It has Open-closed configuration of its end

4 0
2 years ago
A pelican flying along a horizontal path drops
Ludmilka [50]

Answer:

The initial speed of the pelican is 8.81 m/s.

Explanation:

Given;

height of the pelican, h = 5.0 m

horizontal distance, X = 8.9 m

The time of flight is given by;

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*5}{9.81} } \\\\t = 1.01 \ s

The initial horizontal speed of the pelican is given by;

X = vₓt

vₓ = X / t

vₓ = 8.9 / 1.01

vₓ = 8.81 m/s

Therefore, the initial speed of the pelican is 8.81 m/s.

8 0
3 years ago
An astronaut takes an object to the moon where there is less gravity. Explain how the mass and weight of the object on the moon
alexandr1967 [171]
The mass of the object will remain the same rather it's on the moon or on the Earth and even in other places. But the weight will change on the moon, so its weight will be different from the one it had on Earth
3 0
3 years ago
A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg
motikmotik

Answer:

\omega_{f}=1.634\ rad/s  

Explanation:

given,  

diameter of merry - go - round = 2.40 m  

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg  

initial angular momentum of the system  

L_i = I\omega_i  

L_i =356\times 1.80  

L_i =640.8\ kg.m^2/s  

final angular momentum of the system  

L_f = (I_{disk}+mR^2)\omega_{f}  

L_f = (356 + 25\times 1.2^2)\omega_{f}  

L_f= (392)\omega_{f}  

from conservation of angular momentum  

L_i = L_f  

640.8= (392)\omega_{f}  

\omega_{f}=1.634\ rad/s  

8 0
2 years ago
Read 2 more answers
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