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Alja [10]
2 years ago
9

What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.

Physics
1 answer:
inysia [295]2 years ago
8 0
The end that is marked with ’N’ will point to the Arctic. The ‘S’ end will point toward the Antarctic. A bar magnet is ‘just’ a big heavy compass needle. The ‘N’ and ‘S’ marking are made to help travelers find their way around the globe.

Yes, it IS confusing to have the ’N’ end of a compass point toward the north axis of the earth. These conventions were well in place LONG before anyone understood that ‘Opposites Attract’. But now that we DO know that ‘Opposites Attract’ we are left with the unfortunate reality of compasses, bar magnets and the earth. There are gazillions of magnets and only one earth! So the ‘convention’ has been made that the magnets are labeled correctly! This means (unfortunately) that the Arctic area of the globe is actually the south end of the earthly magnet. The earth is a giant (but very weak) electromagnetic and the lines of the magnetic field point to the Arctic Regions which is why all out magnets point that way. The magnetic field line dive INTO the earth in the Arctic Regions and OUT of the earth in the Antarctic regions.

I haven’t used the word ‘pole’ here, because magnetic poles don’t actually exist (as far as we know). Every magnet is actually an electromagnetic with electrical charges in motion creating the magnetic field.
You might be interested in
If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
lana [24]

Answer:

Explanation:

Given that,

Mass of star M(star) = 1.99×10^30kg

Gravitational constant G

G = 6.67×10^−11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W =mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g(star) = GM(star)/R²

g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²

g (star) = 8.49 × 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 × 8.49 × 10¹¹

W = 5.98 × 10¹³ N

The weight of the person on neutron star is 5.98 × 10¹³ N

5 0
3 years ago
Which of the following factors most affect the rate at which waves erode land features along the shore?
OLEGan [10]

Answer:

The biggest factor affecting coastal erosion is the strength of the waves breaking along the coastline. A wave's strength is controlled by its fetch and the wind speed. Longer fetches & stronger winds create bigger, more powerful waves that have more erosive power.

Explanation:

hope it helps !

5 0
2 years ago
Read 2 more answers
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate
schepotkina [342]

Answer:

Explanation:

impedance z=(XL^2+R^2)^1/2

power across te resistor ==i^2r

286/300

I=.976

3 0
3 years ago
A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
barxatty [35]

Answer:

Velocity = 3.25[m/s]

Explanation:

This problem can be solved if we use the Bernoulli equation: In the attached image we can see the conditions of the water inside the container.

In point 1, (surface of the water) we have the atmospheric pressure and at point 2 the water is coming out also at atmospheric pressure, therefore this members in the Bernoulli equation could be cancelled.

The velocity in the point 1 is zero because we have this conditional statement "The water surface drops very slowly and its speed is approximately zero"

h2 is located at point 2 and it will be zero.

(P_{1} +\frac{v_{1}^{2} }{2g} +h_{1} )=(P_{2} +\frac{v_{2}^{2} }{2g} +h_{2} )\\P_{1} =P_{2} \\v_{1}=0\\h_{2} =0\\v_{2}=\sqrt{0.54*9.81*2}\\v_{2}=3.25[m/s]

4 0
3 years ago
Pls help me with this fast. I will mark brainiest
denis23 [38]

Answer:

a) 70, 95

b) 95-70= 25cc

c) density= mass/volume

102/25

=4.08g/cc

5 0
3 years ago
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