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Alja [10]
2 years ago
9

What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.

Physics
1 answer:
inysia [295]2 years ago
8 0
The end that is marked with ’N’ will point to the Arctic. The ‘S’ end will point toward the Antarctic. A bar magnet is ‘just’ a big heavy compass needle. The ‘N’ and ‘S’ marking are made to help travelers find their way around the globe.

Yes, it IS confusing to have the ’N’ end of a compass point toward the north axis of the earth. These conventions were well in place LONG before anyone understood that ‘Opposites Attract’. But now that we DO know that ‘Opposites Attract’ we are left with the unfortunate reality of compasses, bar magnets and the earth. There are gazillions of magnets and only one earth! So the ‘convention’ has been made that the magnets are labeled correctly! This means (unfortunately) that the Arctic area of the globe is actually the south end of the earthly magnet. The earth is a giant (but very weak) electromagnetic and the lines of the magnetic field point to the Arctic Regions which is why all out magnets point that way. The magnetic field line dive INTO the earth in the Arctic Regions and OUT of the earth in the Antarctic regions.

I haven’t used the word ‘pole’ here, because magnetic poles don’t actually exist (as far as we know). Every magnet is actually an electromagnetic with electrical charges in motion creating the magnetic field.
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Hi people; there's a question that has been so confusing for me and a friend of mine.
Alborosie

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32

In our case x = 0, then y will be:

(0^{\circ}C * \frac{9}{5})+32=32

y=32^{\circ}F

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

0^{\circ}C+0^{\circ}C=32^{\circ}F

I hope it helps you!              

7 0
3 years ago
Suppose you and a friend are test driving a new car. You drive out of the car dealership and go 10 miles east and then 8 miles s
damaskus [11]

a =12miles

b =10miles

ab =2miles

Explanation:

at first the car is drown out of dealership and went 10 miles east and then 8 miles south

then your friend drives 8 miles west and 6 miles north.

then the distance it flies to get back to dealership is

10²+8 ²=12miles

8²+6²=10miles

12-10= 2 miles

5 0
3 years ago
A uniform cylinder of mass 1.5 kg and radius 0.3 m rolls down a ramp inclined at an angle 0.12 radians to the horizontal. What i
marishachu [46]

Answer:

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That is a closed switch
3 0
3 years ago
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A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of ki
Neporo4naja [7]

Answer:

a = -1.961\,\frac{m}{s^{2}}, s = 16.318\,m, t = 4.079\,s

Explanation:

The equations of equilibrium for the rock are:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a

\Sigma F_{y} = N - m\cdot g = 0

After some algebraic handling, the following expression is found:

-\mu_{k}\cdot m \cdot g = m \cdot a

-\mu_{k}\cdot g = a

Deceleration experimented by the rock is:

a = - (0.2)\cdot (9.807\,\frac{m}{s^{2}} )

a = -1.961\,\frac{m}{s^{2}}

The distance travelled by the rock before stopping is:

s = \frac{(0\,\frac{m}{s} )^{2}-(8\,\frac{m}{s} )^{2}}{2\cdot (-1.961\,\frac{m}{s^{2}} )}

s = 16.318\,m

And the time is:

t = \frac{0\,\frac{m}{s}-8\,\frac{m}{s}}{(-1.961\,\frac{m}{s^{2}} )}

t = 4.079\,s

5 0
3 years ago
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