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Alja [10]
2 years ago
9

What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.

Physics
1 answer:
inysia [295]2 years ago
8 0
The end that is marked with ’N’ will point to the Arctic. The ‘S’ end will point toward the Antarctic. A bar magnet is ‘just’ a big heavy compass needle. The ‘N’ and ‘S’ marking are made to help travelers find their way around the globe.

Yes, it IS confusing to have the ’N’ end of a compass point toward the north axis of the earth. These conventions were well in place LONG before anyone understood that ‘Opposites Attract’. But now that we DO know that ‘Opposites Attract’ we are left with the unfortunate reality of compasses, bar magnets and the earth. There are gazillions of magnets and only one earth! So the ‘convention’ has been made that the magnets are labeled correctly! This means (unfortunately) that the Arctic area of the globe is actually the south end of the earthly magnet. The earth is a giant (but very weak) electromagnetic and the lines of the magnetic field point to the Arctic Regions which is why all out magnets point that way. The magnetic field line dive INTO the earth in the Arctic Regions and OUT of the earth in the Antarctic regions.

I haven’t used the word ‘pole’ here, because magnetic poles don’t actually exist (as far as we know). Every magnet is actually an electromagnetic with electrical charges in motion creating the magnetic field.
You might be interested in
If a ball is rolling across a floor at a constant speed is it accelerating
KATRIN_1 [288]

You already told us that its speed is constant. That's one part of acceleration.

The other part of acceleration is the direction it's moving.

If it's rolling in a straight line, then there's no acceleration.

If it's curving left or right, then that's acceleration.

8 0
3 years ago
Radioactive isotopes are used in medicine to create images of internal
VMariaS [17]

Answer:

The correct option is D) Fission

Explanation:

There are several methods through which Radioactive isotopes are created.

  1. Using a nuclear reactor that has a field of neutrons, insert a stable sample such as Lutetium-176. When it gets bombarded with neutrons, it acquires some, and fission is said to have occurred. Note that when Lutetium-176 acquires a neutron, it becomes radioactive Lu-177.
  2. Fission is also used to create Fluorine-18. To obtain the same, you need to bombard pure or enriched [^{18} O] water with ~18 MeV protons which are high energy in nature. The bombarding is achieved using a cyclotron or an accelerator.

Cheers

3 0
3 years ago
Time dilation: A missile moves with speed 6.5-10 m/s with respect to an observer on the ground. How long will it take the missil
tatyana61 [14]

Answer:

The time taken by missile's clock is 4.6\times 10^{6} s

Solution:

As per the question:

Speed of the missile, v_{m = 6.5\times 10^{3}} m/s

Now,

If 'T' be the time of the frame at rest then the dilated time as per the question is given as:

T' = T + 1

Now, using the time dilation eqn:

T' = \frac{T}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T'}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T + 1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = (1 + (\frac{v_{m}}{c})^{2})^{- \frac{1}{2}}         (1)

Using binomial theorem in the above eqn:

We know that:

(1 + x)^{a} = 1 + ax

Thus eqn (1) becomes:

1 + \frac{1}{T} = 1 - \frac{- 1}{2}.\frac{v_{m}^{2}}{c^{2}}

T = \frac{2c^{2}}{v_{m}^{2}}

Now, putting appropriate values in the above eqn:

T = \frac{2(3\times 10^{8})^{2}}{(6.5\times 10^{3})^{2}}

T = 4.6\times 10^{6} s

4 0
3 years ago
Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0
3 years ago
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
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