1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
3 years ago
5

A family is skating at an ice rink. The 58.2 kg mother is holding the

Physics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.

Explanation:

use this formula :

a_{y} = \frac{Fdadshandy}{msys}

then you fill it in :

a_{y} = \frac{100N}{35.5kg+58.2kg}

a_{y} = \frac{100N}{93.7kg}

a_{y} = 1.0672 m/s^{2}

then you multiply that with the daughters weight :

T_{2} x= m_{2} a_{y}

T_{2} x = 35.5kg (1.0672 m/s^{2})

T_{2} x = 37.89N

and that's the answer :) : 37.89N

You might be interested in
To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th
Kryger [21]

Answer:

H = 10.05 m

Explanation:

If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s

so here the total time of the motion above the top point of pole is given as

\Delta t = 4.1 - 0.5 = 3.6 s

now we have

\Delta t = \frac{2v}{g}

3.6 = \frac{2v}{9.8}

v = 17.64 m/s

so this is the speed at the top of flag pole

now we have

v_f - v_i = at

17.64 - v_i = (-9.8)(0.5)

v_i = 22.5 m/s

now the height of flag pole is given as

H = \frac{v_f + v_i}{2}t

H = \frac{22.5 + 17.64}{2} (0.5)

H = 10.05 m

5 0
3 years ago
If you attach a 100 g mass to the spring whose data are shown in the graph, what will be the period of its oscillations?
ycow [4]

if for a force of 0.5 N we have a displacement of -0.02m we can calculate the elastic constant(k) with the formula F=-kx(F=0.5N x=-0.02)

k=F/x k=0.5/0.02=25N/m

now we can calculate the period by the formula

T=2π√(m/k)

in the mass we convert grams to kilograms so 100g=0.1kg

T=6.28√(0.1/25)⇒T=0.39seconds

8 0
3 years ago
Read 2 more answers
Person 1 moves an object 10 meters and exerts a force of 50N in 5 seconds. Person 2 moves an object 10 meters and exerts a force
mel-nik [20]

Answer:

Explanation:

Work is a force time the distance moved in the direction of that force, time is not a variable. Provided that the 50 N forces were applied in the same direction, the work done is identical. Assuming both applied force and direction of motion are horizontal W = Fd = 50(10) = 500J.

If the reason that one was slower is because the  second person applied his force at an angle, let's say 60° below the horizontal, then the work done by the second person is 50cos60(10) = 250 J

Time IS a consideration for Power, the RATE of doing work. Provided the force and motion are horizontal, the first person applied twice as much Power as the second person doing an identical amount of work in half the time.

7 0
3 years ago
A 60.watt light bulb runs for 5.0 seconds. How much energy does it use?
VikaD [51]

"watt" means "Joule of energy per second"

"60 watts" means "60 Joules per second"

(60 joules per second) x (5 seconds) = <em>300 Joules of energy</em>

5 0
4 years ago
A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?
dexar [7]

Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1.45 = ½ × 9.8 × t²

1.45 = 4.9 × t²

Divide both side by 4.9

t² = 1.45/4.9

Take the square root of both side

t = √(1.45/4.9)

t = 0.54 s

Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).

Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

Time of flight (T) =?

T = 2t

T = 2 × 0.54

T = 1.08 s

Therefore, it will take the kangaroo 1.08 s to return to the earth.

3 0
3 years ago
Other questions:
  • The theory that light exists in quantized "chunks" was proposed in response
    7·2 answers
  • If f(x)=4/x+2 and g is the inverse of f,then g'(10)=​
    14·1 answer
  • A mass m is tied to an ideal spring with force constant k and rests on a frictionless surface. The mass moves along the x axis.
    9·1 answer
  • Find the volume of the solid generated by revolving the shaded region about the​ x-axis. The curve is y equals StartFraction 15
    10·1 answer
  • PLEASE HELP BRAINLIEST + POINTS'
    15·1 answer
  • Does exercises relief your boredom during exercise?​
    15·2 answers
  • ASAP Question 3 of 10
    11·1 answer
  • Which choice describes the purpose of the blades in a wind turbine?
    12·1 answer
  • A nail is hit with a hammer with a force of 10 Newtons. The nail moves into the wood with a force ____.
    10·1 answer
  • Why is it easier to swim in sea than in a pond or river?​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!