Answer:

Explanation:
If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s
so here the total time of the motion above the top point of pole is given as

now we have



so this is the speed at the top of flag pole
now we have



now the height of flag pole is given as



if for a force of 0.5 N we have a displacement of -0.02m we can calculate the elastic constant(k) with the formula F=-kx(F=0.5N x=-0.02)
k=F/x k=0.5/0.02=25N/m
now we can calculate the period by the formula
T=2π√(m/k)
in the mass we convert grams to kilograms so 100g=0.1kg
T=6.28√(0.1/25)⇒T=0.39seconds
Answer:
Explanation:
Work is a force time the distance moved in the direction of that force, time is not a variable. Provided that the 50 N forces were applied in the same direction, the work done is identical. Assuming both applied force and direction of motion are horizontal W = Fd = 50(10) = 500J.
If the reason that one was slower is because the second person applied his force at an angle, let's say 60° below the horizontal, then the work done by the second person is 50cos60(10) = 250 J
Time IS a consideration for Power, the RATE of doing work. Provided the force and motion are horizontal, the first person applied twice as much Power as the second person doing an identical amount of work in half the time.
"watt" means "Joule of energy per second"
"60 watts" means "60 Joules per second"
(60 joules per second) x (5 seconds) = <em>300 Joules of energy</em>
Answer:
1.08 s
Explanation:
From the question given above, the following data were obtained:
Height (h) reached = 1.45 m
Time of flight (T) =?
Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:
Height (h) = 1.45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
1.45 = ½ × 9.8 × t²
1.45 = 4.9 × t²
Divide both side by 4.9
t² = 1.45/4.9
Take the square root of both side
t = √(1.45/4.9)
t = 0.54 s
Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).
Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:
Time (t) taken to reach the height = 0.54 s
Time of flight (T) =?
T = 2t
T = 2 × 0.54
T = 1.08 s
Therefore, it will take the kangaroo 1.08 s to return to the earth.