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sergiy2304 [10]
1 year ago
15

Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m.

Mathematics
2 answers:
IgorLugansk [536]1 year ago
8 0

The roots of the equation are non real roots.

<h3>What does discriminant of roots?</h3>

Discriminant, in mathematics, a parameter of an object or system calculated as an aid to its classification or solution. In the case of a quadratic equation ax^{2} + bx + c = 0, the discriminant is b2 − 4ac; and it tells what kind of roots it is real, non real.

As of now, 2m²+3=m we need to find the kind of roots they have.

2m²+3=m

2m²-m+3=0

Here, we can derive the following values from the equation:

a= 2, b = -1, c = 3

An equation's discriminant is stated as:

D= b²-4ac

D = (-1)(-1) - 4(2)(3)

D = 1 - 24

D = -23

Discriminant determine the kind of roots that the equation contains.

In this instance, the discriminant is below 0.

The equation's roots are complex conjugates when D < 0.

Hence the roots for the equation are non real roots.

To get more information about discriminant:

brainly.com/question/15884086

#SPJ4

Tpy6a [65]1 year ago
4 0

The roots of the equation , 2m^{2}+3=m, are non real roots.

<h3>Discriminants are what?</h3>

The quadratic formula's discriminant is represented by the square root symbol b^{2}-4ac. If there are two solutions, one solution, or none at all, the discriminant informs us.

As of now, 2m²+3=m we need to find the kind of roots they have.

2m²+3=m

2m²-m+3=0

Here, we can derive the following values from the equation:

a = 2, b = -1, c = 3

An equation's discriminant is stated as:

D = b²-4ac

D = (-1)(-1) - 4(2)(3)

D = 1 - 24

D = -23

Discriminant can determine the kind of roots that the equation contains.

In this instance, the discriminant is below 0.

The equation's roots are complex conjugates when D < 0.

Hence the roots for the equation are non real roots.

To get more information about discriminant follow the link:

https://brainly.in/question/27214502

#SPJ4

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Hello!

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Hope this helped and any questions please just ask. Thank you!
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