Question

In a gravitational-free environment, an object of unknown mass is connected to a spring with k = 40 N/m. The spring is compressed .2 m to and released. At the moment the spring is released, the object accelerated at 3 $m/s^{2}$. What is the mass of the object?
pls explain asap!!!

Answer 1

Newton's Third Law of Motion states that springs exert a restoring force when they are pulled. The relationship between the spring force, spring constant, and spring displacement is governed by Hooke's Law.

Mass of the object= k*x/a= 26kg

what is Hooke's law?

The force (F) required to extend or compress a spring by a certain distance (x) scales linearly with respect to that distance, according to the empirical law known as Hooke's law.

according to  Hooke's law

f=-k x (-ve because spring is compressing)

from force equation f=ma m-=mass, a= acceleration , k=spring constant, x= displacemt due to compression

so, ma=-k x, (mass can not be -ve so remove -ve sign)

m=k x/a= 40*2/3=26.67 kg

To learn more about :  Hooke's law

Ref : brainly.com/question/7324904

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