Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :

Hence, this is the required solution.
Answer:
Yes, the capacitor's Q load varies inversely proportional to the distance between plates.
Explanation:
In the attached files you see the inverse relationship between capacity and distance between plates "d".
In the following formula we see its relationship with the "Q" load
Answer:
v = 88.89 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.
We must make up the following equation:

where:
F = force applied = 4000 [N]
t = time = 0.001 [s]
m = mass = 0.045 [kg]
v = velocity [m/s]
![4000*0.001=0.045*v\\v=88.89[m/s]](https://tex.z-dn.net/?f=4000%2A0.001%3D0.045%2Av%5C%5Cv%3D88.89%5Bm%2Fs%5D)
Answer:
F = 1280 N
Explanation:
Given that,
Acceleration experienced by a space shuttle, a = 32 m/s²
Mass of the astronauts, m = 40 kg
We need to find the force experienced by the astronaut.
We know that the net force is equal to the product of acceleration and its mass. So,
F = ma
F = 40 kg × 32 m/s²
So,
F = 1280 N
So, 1280 N of force is experienced by the Astronaut.