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weeeeeb [17]
3 years ago
9

A train travels from Albuquerque, New Mexico, to Mexico City in 4 hours with an average velocity of 80 km/h to the south. What i

s the train’s displacement?
Physics
2 answers:
Ivenika [448]3 years ago
6 0
The displacement of the train is equal to the velocity of the train multiplied by the time of travel. In this case,the average velocity is equal to 80 km/h and the time of travel is four hours. The answer is 80 km/h *4 h or equal to 320 km in total. Answer is 320 kilometers.
nikitadnepr [17]3 years ago
6 0

Answer: The displacement is the difference in position (between the final position and the initial), so train's displacement will be the initial position subtracted of the position when the train has traveled for 4 hours.

If we define the original position as 0, then the total displacement is, if the train has a velocity of 80km/h, then in 4 hours the train travels 80*4 km= 320 km to the south. Because the train travels in one direction and never turns, the total displacement is 320km

You might be interested in
Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?
kolbaska11 [484]

Average speed is defined as the ratio of total distance covered in total given time

speed = \frac{distance}{time}

here we know that total distance that man moved is

d_1 = 200 km

d_2 = 100 km

so total distance is

d = d_1 + d_2

d = 200 km + 100 km

d = 300 km

now here total time of the motion is

t_1 = 6 hours

t_2 = 4 hours

total time will be given as

t = t_1 + t_2

t = 6 + 4 = 10 hours

now by above formula

v_{avg} = \frac{300}{10}

v_{avg} = 30 km/h

so his average speed is 30 km/h

8 0
4 years ago
What will it be ? Plz help me
IgorC [24]

Answer:

For number 2, it will be 8.

3 0
3 years ago
The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2
Darya [45]

Answer:

1.87 A

Explanation:

τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s

d = diameter of copper wire = 2 mm = 2 x 10⁻³ m

Area of cross-section of copper wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

A = 3.14 x 10⁻⁶ m²

E = magnitude of electric field = 0.01 V/m

e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³

i = magnitude of current

magnitude of current is given as

i = \frac{Ane^{2}\tau E}{m}

i = \frac{(3.14\times 10^{-6})(8.47\times 10^{28})(1.6\times 10^{-19})^{2}(2.5\times 10^{-14}) (0.01)}{(9.1\times 10^{-31})}

i  = 1.87 A

4 0
3 years ago
Starting from rest, a 2.1x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
nirvana33 [79]

Answer:

1.327363 m/s

0.00090243 m

Explanation:

u = Initial velocity

v = Final velocity

m = Mass of flea

Energy

E=\frac{1}{2}m(v^2-u^2)\\\Rightarrow 3.7\times 10^{-4}=2.1\times 10^{-4}(v^2-0)\\\Rightarrow v=\sqrt{\frac{3.7\times 10^{-4}}{2.1\times 10^{-4}}}\\\Rightarrow v=1.32736\ m/s

The velocity of the flea when leaving the ground is 1.327363 m/s

W=F\times s\\\Rightarrow s=\frac{W}{F}\\\Rightarrow s=\frac{3.7\times 10^{-4}}{0.41}\\\Rightarrow s=0.00090243\ m

The flea will travel 0.00090243 m upward

8 0
3 years ago
5. What is the amount of force required to accelerate a 20 kg object at a rate of 5 m/sz?
GenaCL600 [577]

Force required is 100 N

<u>Given that;</u>

Rate of acceleration = 5 m/s²

Mass of object = 20kg

<u>Find:</u>

Force required

<u>Computation:</u>

Force = Mass × Acceleration

Force required = Rate of acceleration × Mass of object

Force required = 20 × 5

Force required = 100 N

Learn more:

brainly.com/question/17506203?referrer=searchResults

3 0
3 years ago
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