Answer:
The ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.
Step-by-step explanation:
We have the function that represents the height h (x) of the ball 
Where x is the horizontal distance of the ball.
We want to find the horizontal distance the ball is at (horizontal distance between the field marshal and the ball) when it is at a height of 10 feet.
To do this, we must do h (x) = 10

Now we must solve the second degree equation. For this we use the formula of the resolvent:

and

ft
and
ft
Then, the ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.
Answer:
b
Step-by-step explanation:
All are congruent segments. Beacuse congruent segments are two segments that are equal in length.
Answer:
5 of the 7 boxes are 8 inches in height
Step-by-step explanation:
Mathematically;
1 ft = 12 inches
So, 5 ft will measure 5 * 12 = 60 inches
So from what we have ,
We want to combine 8 and 10 inches to give 60 inches total
Let the number of 10 inches be x and the number of 8 inches be y
Mathematically;
x + y = 7 •••••(i)
10x + 8y = 60 ••••(ii)
From equation i, x = 7-y
Put this in equation ii
10(7-y) + 8y = 60
70-10y + 8y = 60
70-60 = 10y-8y
2y = 10
y = 10/2
y = 5