Answer:
I may be wrong sir/ma’am, but I believe it’s 1. Surface temperatures. 3.radio signals from space. And 4. Distance of stars.
Explanation:
sorry y’all:(
The term is frequency.
The frequency is the number of vibrations per unit of time or the number of waves that passes a point per unit of time.
Every crest (and every trough) represents a pass of the wave so you can count the number of crests in an intervavl of time to find the frequency as the number of crests divided by the time elapsed.
Answer: 1.9 m/s
Explanation:
1) Data:
height, y = 0
range, x = 0.77m
angle, α = 45°
question, horizontal velocity, Vox = ?
2) Physical principles and formulas
Projectile motion.
3) Solution
Factor
![0=t[V_0sin(45)-gt/2]](https://tex.z-dn.net/?f=%200%3Dt%5BV_0sin%2845%29-gt%2F2%5D%20)
Discard t = 0 and solve for the other factor:
![gt/2=V_0sin(45)\\ \\ V_0= gt/(2sin(45))=9.81[0.77/V_{0}cos(45)]/[2sin(45)]\\ \\ V_0^2=9.81[0.77/(2cos(45)sin(45)=9.81[0.77/sin(90)]=7.55\\ \\ V_0}=\sqrt{7.55} =2.8](https://tex.z-dn.net/?f=%20gt%2F2%3DV_0sin%2845%29%5C%5C%20%5C%5C%20%20V_0%3D%20gt%2F%282sin%2845%29%29%3D9.81%5B0.77%2FV_%7B0%7Dcos%2845%29%5D%2F%5B2sin%2845%29%5D%5C%5C%20%5C%5C%20V_0%5E2%3D9.81%5B0.77%2F%282cos%2845%29sin%2845%29%3D9.81%5B0.77%2Fsin%2890%29%5D%3D7.55%5C%5C%20%5C%5C%20V_0%7D%3D%5Csqrt%7B7.55%7D%20%3D2.8%20%20)
Find Vx:
![Vx=V_{0x}=V_{0}cos(45)=2.75(\sqrt{2} /2]=1.9](https://tex.z-dn.net/?f=%20Vx%3DV_%7B0x%7D%3DV_%7B0%7Dcos%2845%29%3D2.75%28%5Csqrt%7B2%7D%20%2F2%5D%3D1.9%20%20)
Vx = 1.9m/s ← answer
