Answer:
The tension force in the supporting cables is 7245N
Explanation:
There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:
![F_{net} = F_g - F = m\cdot g - F\\](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20F_g%20-%20F%20%3D%20m%5Ccdot%20g%20-%20F%5C%5C)
We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:
![1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N](https://tex.z-dn.net/?f=1150kg%5Ccdot%203.5%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D%201150kg%20%5Ccdot%209.8%5Cfrac%7Bm%7D%7Bs%5E2%7D-F%5C%5C%5Cimplies%20F%20%3D%201150kg%5Ccdot%289.8-3.5%29%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D%207245N)
The tension force F in the supporting cables is 7245N
It would have to be c because it is a chemical change. your welcome!!!!!
I would say B. Because actual mass would ricochet off the sidewalk.
Answer:
4m/s
Explanation:
May be different considering how long the pole is and how heavy the firefighter is.