Draw two unique free body diagrams that each show a net force of 30 N to the left.

A race-car driver achiveved a speed of speed of m/s in 14 seconds after taking off from ready at the starting line . What was th

vladimir2022 [97]

Average acceleration = (change in speed) / (time for the change)

Average acceleration =

(speed at the end of the 14 seconds) / (14 seconds)

5 0

3 years ago

Even though earth has ____ mass than the sun, the moon orbits earth because it much nearer to it.

kozerog [31]

Even though the Earth has less mass than the Sun, the moon orbits Earth because it’s much nearer to it.

<u>Explanation :</u>

The fact is that the Moon orbits both the Sun and the Earth. On looking at the orbit of the Moon, it orbits in the same manner the way Earth does, but in a Spiro graph pattern along with orbiting the Earth with a small wobble to it.

Since the Sun has greater distance from the Moon as compared to the Earth (around 400 times), the gravity of Earth draws better impact on the Moon.

The escape velocity of the Moon is about 1.2 km/s at the distance from the Earth which is not sufficient to get ripped away from the Earth.

Hence, the moon orbits the Earth along with orbiting the Sun together with the Earth, but seems as if it only orbits the Moon.

3 0

3 years ago

Read 2 more answers

four forces act on an object of mass 100kg, they are 12N(N), 70N(S), 33N(E), 10N(w). calculate the reseulting acceleration of th

trapecia [35]

Answer:

0.62 m/s² at 68° S of E

Explanation:

Net force north = 12 - 70 = -58 N

Net force east = 33 - 10 = 23 N

Net force = √(-58² + 23²) = 62.3939... N

acceleration = F/m = 62.3939/100 = 0.623939... ≈ 0.62 m/s²

θ = arctan(-58/23) = -68.3691... ≈ 68° S of E

6 0

3 years ago

A box accidentally drops from a truck traveling at a speed of 20.0 m/s and slides along the ground for a distance of 30.0 m Calc

Hoochie [10]

Answer:

a= - 6.667 m/s²

Explanation:

Given that

The initial speed of the box ,u= 20 m/s

The final speed of the box ,v= 0 m/s

The distance cover by box ,s= 30 m

Lets take the acceleration of the box = a

We know that

v²= u ² + 2 a s

Now by putting the values in the above equation we get

0²=20² + 2 a x 30

$a=- \dfrac{20^2}{2\times 30} \ m/s^2$

a= - 6.667 m/s²

Negative sign indicates that velocity and acceleration are in opposite direction.

Therefore the acceleration of the box will be - 6.667 m/s² .

6 0

2 years ago

Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus

charle [14.2K]

Answer:

The total energy of the composite system is 7.8 J.

Explanation:

Given that,

Height = 0.15 m

Radius of circular arc = 0.27 m

Suppose, the entire track is friction less. a bullet with a m₁ = 30 g mass is fired horizontally into a block of wood with m₂ = 5.29 kg mass. the acceleration of gravity is 9.8 m/s.

Calculate the total energy of the composite system at any time after the collision.

We need to calculate the total energy of the composite system

Total energy of the system at any time = Potential energy of the system at the stopping point

$E=mgh+Mgh$

$E=(m+M)gh$

Put the value in to the formula

$E=(30\times10^{-3}+5.29)\times 9.8\times0.15$

$E=7.8\ J$

Hence, The total energy of the composite system is 7.8 J.

8 0

3 years ago

Draw two unique free body diagrams that each show a net force of 30 N to the left.​

Draw two unique free body diagrams that each show a net force of 30 N to the left.