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3 years ago

Find the potential energy of a 2kg ball 15m in the air

1 answer:

8 0

<span>The ball's gravitational potential energy at its peak height was 0.4 joules, and its .... Ignore air resistance and determine (a) the kinetic energy at 28.1 m, (b) the .... At position B, just before it lands, it is falling at 15m/s. a) if the blocks potential ...</span>

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Darren drives to school in rush hour traffic and averages 28 mph. He returns home in mid-afternoon when there is less traffic an

Gala2k [10]

Answer:

distance between school and home is 21 miles

Explanation:

given data

in rush hour speed s1 = 28 mph

less traffic speed s2 = 42 mph

time t = 1 hr 15 min = 1.25 hr

to find out

distance d

solution

we consider here distance home to school is d and t1 time to reach at school

we get here distance equation when we go home to school that is

distance = 28 × t1 .......................1

and when we go school to home distance will be

distance = 42 × ( t - t1 )

distance = 42 × ( 1.25 - t1 ) ...................2

so from equation 1 and 2

28 × t1 = 42 × ( 1.25 - t1 )

t1 = 0.75

from equation 1

distance = 28 × t1

distance = 28 × 0.75

distance = 21 miles

4 0

3 years ago

How much force is needed to accelerate a 2500 kg car at a rate of 3.5 m/s^2?

Sati [7]

F = ma

F = applied force in newtons = to be determined

m = mass of the car = 2,500 kg

a = acceleration of the car = 3.5 m/s²

F = (2,500 kg)(3.5 m/s²)

F =8750

4 0

4 years ago

If 180 grams of potassium iodide is dissolved in 100 cm3 of water at 30oC, a(n) _______________ solution is formed. A) saturated

kenny6666 [7]

Answer: D)supersaturated

Explanation: Solubility is defined as the amount of solute in grams which can dissolve in 100 g of the liquid to form a saturated solution at that particular temperature.

At $30^0C$ , the solubility of $KI$ is 153g/100 ml.

Thus if 180 grams is dissolved, it contains more amount of solute than it can hold at that that temperature, and thus is supersaturated solution.

A saturated solution is a solution containing the maximum concentration of a solute dissolved in the solvent. The additional solute does not dissolve in a saturated solution.

An unsaturated solution is solution in which the solute concentration is lower than its equilibrium solubility.

A supersaturated solution is one that has more solute than it can hold at a certain temperature.

6 0

3 years ago

Read 2 more answers

A student travels 4.0m East, 8.0m South, 4.0m west, and finally 8.0m north. What is her displacement? What distance did she trav

erica [24]

no cap bro bro i thinks its poop Explanation:

3 0

3 years ago

What is 64 nanometers to m?

defon

$\sf Hello!$

$\sf We\: know \:that,$
$\sf 1\: meter$ = $\sf 10^{9} nm$

$\sf Then,$

$\sf Distance\: in \:m$ = $\sf Distance\: in\: nm$ × $\dfrac{\sf 1}{\sf 10^{9}}\: \sf m$

⇒ $\sf Distance\: in \:m$ = $\sf 64 × 10^{-9} \:m$

⇒ $\sf Distance\: in\: m$ = $\sf 6.4 × 10^{-8} \:m$

~ $\sf iCarl$

3 0

3 years ago

Read 2 more answers