Answer:
500km
Explanation:
Given parameters:
Speed = 200km/hr
Time taken = 2.5hrs
Unknown:
Distance = ?
Solution:
To solve this problem, we use the speed, time and distance equation.
Therefore;
Distance = Speed x time
So;
Distance = 200 x 2.5 = 500km
Answer:
Explanation:
In a L C R circuit, the average power is given by

As given in the question
CosФ = R / Z
And we know that

So


Answer:
Change in Q = 2.1x 10^-3 C
Explanation:
We are given that
The Initialcapacitance C1 = 6.0μF
Initial charge oncapacitor
Q1 = C1 V
= 6.00 x 10^-6 x 100
= 6.00 x 10^-4 C
So the Final capacitance C2 will be
= K x C1 = 4.5 x 6.00 x 10^-6
= 2.7 x 10^ -5 F
So to get Finalcharge
We use Q2 = C2 x V
= 2.7 x 10^ - 5 x 100
= 27 x 10^ -4 C
So Charge flown in thecapacitor is change in Q
Which is = Q2 - Q1
= 27 x 10^-4 - 6.0 x 10^ -4
Change in Q = 2.1x 10^-3 C
Answer:
System software acts as a platform on which an application software program runs.
Answer
given,
width of slit, d = 0.08 mm
d = 8 x 10⁻⁵ m
light of two wavelength
I₁= 446 nm
I₂ = 662 nm
a) angles at which the third dark fringe

m = 3 , I₁= 446 nm

C = 0.958°
m = 3 , I₁= 662 nm

C = 1.423°
b) angles at which the third dark fringe

m = 1 , I₁= 446 nm

C = 0.319°
m = 1 , I₁= 662 nm

C = 0.474°