What is true about the inertia of two cars , car A of mass 1,500 kilograms and car B of mass 2,000 kilograms?

How much does the speed of a car increase if it accelerates

Nata [24]

Answer:

12.5 m/s

Explanation:

a = Δv / Δt

2.5 m/s² = Δv / 5 s

Δv = 12.5 m/s

4 0

2 years ago

A car is being driven down a level track with no net force on it. This motion is best described as

Alex

A)Linear motion

If there is not net force on the car, then by the Newton Second Law, the acceleration is zero, and the only valid option for zero acceleration is A).

3 0

2 years ago

Gravitational attraction depends on the mass of the objects as well as their distance. The gravitational force between objects i

shepuryov [24]

<h2>Answer: Gravitational attraction will be the same</h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

$F=G\frac{m_{1}m_{2}}{r^2}$ (1)

Where:

$F$ is the module of the force exerted between both bodies

$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

Now, if we double both masses and the distance also doubles, this means:

$m_{1}$ and $m_{2}$ will be now $2m_{1}$ and $2m_{2}$

$r$ will be now $2r$

Let's rewrite the equation (1) with this new values:

$F=G\frac{(2m_{1})(2m_{2})}{(2r)^2}$ (2)

Solving and simplifying:

$F=4G\frac{m_{1}2m_{2}}{4r^2}$

$F=G\frac{m_{1}m_{2}}{r^2}$ (3)

As we can see, equation (3) is the same as equation (1).

So, if the masses both double and the distance also doubles the <u>Gravitational attraction between both masses will remain the same.</u>

7 0

2 years ago

Read 2 more answers

Examples of fixed pulley?

Neko [114]

Answer:

One example of a fixed pulley is a Flag Pole

Explanation:

A good example of a fixed pulley is a flag pole: When you pull down on the rope, the direction of force is redirected by the pulley, and you raise the flag. Other examples of movable pulleys include construction cranes, modern elevators, and some types of weight lifting machines at the gym.

4 0

2 years ago

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is 8.9 nC ( 8.9 10-9 C), how man

Alika [10]

Answer:

Number of electrons, $n=5.56\times 10^{10}$

Explanation:

Given that,

Charge on the fur, $q=8.9\ nC=8.9\times 10^{-9}\ C$

A piece of amber is charged by rubbing with a piece of fur. We need to find the electrons were added to the amber. It can be calculated using the quantization of charge as

q = n × e

Where

n is the number of electrons

e is the charge on electron

$n=\dfrac{q}{e}$

$n=\dfrac{8.9\times 10^{-9}}{1.6\times 10^{-19}}$

$n=5.56\times 10^{10}\ electrons$

So, $n=5.56\times 10^{10}\ electrons$ number of electrons are added to the amber. Therefore, this is the required solution.

7 0

3 years ago