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AlladinOne [14]
1 year ago
13

"Inert" xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH° values for xenon difluorid

e, tetrafluoride, and hexafluoride are -2105, - 2284, and - 2402 kJ/mol, respectively. Find the average bond energy of the Xe¬F bonds in each fluoride.
Chemistry
1 answer:
svp [43]1 year ago
3 0

The average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

Given:

ΔH° of xenon difluoride (XeF2) = -105 kJ/mol

ΔH° of xenon tetrafluoride (XeF4)= -284 kJ/mol

ΔH° of xenon hexafluoride (XeF6) = -402 kJ/mol

The bond energy of Xe-F in XeF2 can be calculated as follows,

As we know that

ΔH° = ΔH°(bond formed) + ΔH°(bond broken)

The chemical reaction for the formation of XeF2 can be written in such a way,

Xe (g) + F2 (g) → XeF2 (g)

= [1 mol F2 (159 kJ/mol)] + [2(-Xe-F)] - 105 kJ/mol

= 159 kJ/mol + 2(-Xe-F) - 264 kJ/mol

= 2(-Xe-F)

Xe-F = 132 kJ/mol

Thus, we concluded that the average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

learn more about bond energy:

brainly.com/question/11653058

#SPJ4

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What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
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Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

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⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

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3 years ago
Gold is currently trading at very high price. Suppose that gold is selling for around $1860/ounce. How
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Answer:

The answer is "3.81041978"

Explanation:

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\to \$ \ 0.25 =  15.2416791  \times 0.25 \  miligrams\\

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3 years ago
In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to anot
forsale [732]

The given question is incomplete . The complete question is :

In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?

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Explanation:

Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

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