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Svetlanka [38]
1 year ago
7

Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it

just begins to rise in the air of density 1.29kg/m3. (g=10m/s2) Detailed Explanation Please
Physics
1 answer:
Nonamiya [84]1 year ago
7 0

the weight of the balloon is .030 * 10 = 0.3 N

the weight of the gas of volume v is 0.54*10 N

The lifting force of a volume of v m³ of displaced air is 1.29v N

so, we need

1.29*10*v = 0.3 + 0.54*10*v

or

1.29v = 0.03+0.54v

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MGS and later orbiters found spectral evidence for what minerals on the Martian surface? Check all that apply.
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Mars Global Surveyors (MGS) and later orbiters found the following  minerals on the  Martian surface;

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The Mars Global Surveyors (MGS) and later orbiters suggest that the Martian crust contains a higher percentage of volatile elements such as Sulphur and chlorine than the Earth's crust does.

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3 years ago
A loaded barge has a mass of 1 500 000 kg and is traveling at 3 m/s. If a tugboat applies an opposing force of 12 000 N for 10 s
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Answer:

Explanation:

Initial momentum is 1.5e6(3) = 4.5e6 kg•m/s

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The tug applied impulse is 12000(10) = 120000 N•s or 0.12e6 kg•m/s

The remaining momentum is 4.5e6 - 0.12e6 =  4.38e6 kg•m/s

The barge velocity is now 4.38e6 / 1.5e6 = 2.92 m/s

The tug applies 0.012e6 N•s of impulse each second.

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To stop the barge in one minute(60 s), the tug would have to apply

4.5e6 / 60 = 75000 N•s /s or 75 000 N

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