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Svetlanka [38]
1 year ago
7

Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it

just begins to rise in the air of density 1.29kg/m3. (g=10m/s2) Detailed Explanation Please
Physics
1 answer:
Nonamiya [84]1 year ago
7 0

the weight of the balloon is .030 * 10 = 0.3 N

the weight of the gas of volume v is 0.54*10 N

The lifting force of a volume of v m³ of displaced air is 1.29v N

so, we need

1.29*10*v = 0.3 + 0.54*10*v

or

1.29v = 0.03+0.54v

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A dog walks along The ground. If the dog applies an action force on the ground, what is the reaction force?
fiasKO [112]

Explanation:

Action and reaction are two forces that are equal in magnitude but the direction is opposite.

When a dog walks along the ground, the action force is the force that dog applies on the ground. On the other hand, the reaction force is the force that the ground applies on the dog. It is based on Newton's third law of motion.

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Dolphins and other sea creatures can leap to great heights by swimming straight up and exiting the water at a high speed. A 200
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A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

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4 years ago
The pitch of a sound wave refers to the loudness of a wave. True False
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6 0
3 years ago
Read 2 more answers
Find the center of mass (in cm) of a one-meter long rod, made of 50 cm of copper (density 8.92 g/cm3) and 50 cm of iron (density
Gennadij [26K]

Answer

given,

copper rod length = 50 cm

density of the copper = 8.92 g/cm³

iron rod length = 50 cm

density of iron = 7.86 g/cm³

mass of iron = density × volume

               m_i = 7.86 × A × l/2

               m_c = 8.96 × A × l/2

taking  the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be  -ve side.

center of mass

 = \dfrac{m_i\times \dfrac{-l}{4}+m_c\times \dfrac{l}{4}}{m_i+m_c}

 = \dfrac{7.86\times A \times \dfrac{l}{2}\times \dfrac{-l}{4}+8.96\times A \times \dfrac{l}{2}\times \dfrac{l}{4}}{7.86\times A \times \dfrac{l}{2}+8.96\times A \times \dfrac{l}{2}}

 = \dfrac{7.86\times \dfrac{-l}{4}+8.92\times \dfrac{l}{4}}{7.86+8.92}

 = \dfrac{1.06\dfrac{l}{4}}{16.78}

 = 0.015793 m

 = 1.579 m (+ve)

center of mass shift to cooper because cooper is heavy.

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