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Svetlanka [38]
1 year ago
7

Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it

just begins to rise in the air of density 1.29kg/m3. (g=10m/s2) Detailed Explanation Please
Physics
1 answer:
Nonamiya [84]1 year ago
7 0

the weight of the balloon is .030 * 10 = 0.3 N

the weight of the gas of volume v is 0.54*10 N

The lifting force of a volume of v m³ of displaced air is 1.29v N

so, we need

1.29*10*v = 0.3 + 0.54*10*v

or

1.29v = 0.03+0.54v

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Answer:

Vx = 15V

Explanation:

To find the speed of the third car you take into account that the distance that they travel is the same. Only time is different in one second. Mathematically you have:

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then, you can equal the third and first equation:

3vt=v_x(t-2)\\\\3(2.5s)v=(2.5s-2s)v_x\\\\7.5v=0.5v_x\\\\v_x=15v

hence, Vx = 15V

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TRANSLATION:

Para encontrar la velocidad del tercer automóvil, tenga en cuenta que la distancia que recorren es la misma. Solo el tiempo es diferente en un segundo. Matemáticamente tienes:

iguala la primera y segunda ecuación obtiene el tiempo t:

entonces, puedes igualar la tercera y primera ecuación:

por lo tanto, Vx = 15V

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