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4 years ago

If your prediction turns out to be false your experiment has been a failure

Physics

2 answers:

irinina [24]4 years ago

7 0

Answer:

False.

Explanation:

The hypothesis can be defined as the explanations or suppositions that are acceptable in order to prove some natural phenomena by the help of experimental procedure.

And you can use your data which is gather from the experiment and formulate a new hypothesis.

A hypothesis is the data which is not depend on the experimental data, it can be say that it is just a not dependent hypothesis.

nikdorinn [45]4 years ago

3 0

This is false. Your hypothesis, or prediction, is just that: a prediction. Saying its a failure will result in bias.

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An object has a velocity of 8 m/s and a kinetic energy of 480 J what is the mass of the object

MaRussiya [10]

We have first velocity equals 8 m/s and the kinetic energy is 480 J

The order is the mass of the object

We have this formula K= mv2/2 isolating the mass we have m=k/v2

Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg

7 0

4 years ago

Please help me! I don’t get this

goldfiish [28.3K]

The answer will be

(1) correct

(2) correct

(3) the force of the soccer ball on the net

(4) Will not change

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4 0

3 years ago

Read 2 more answers

Waves propagate along a stretched string at a speed of 6.9 m/s. The end of the string

Alenkinab [10]

Answer:

24.64m

Explanation:

The formula for calculating the wavelength is expressed as;

wavelength = Speed/frequency

Given

Speed = 6.9m/s

Frequency = 1/Period

Frequency = 1/3.6

Frequency = 0.28Hz

Get the wavelength

wavelength = 6.9/0.28

wavelength = 24.64m

Hence the wavelength of the waves traveling along the string is 24.64m

4 0

3 years ago

Suppose you spray your sister with water from a garden hose. The water is supplied to the hose at a rate of 0.625×10−3 m3/s and

Tems11 [23]

Answer:

0.153 m/s

Explanation:

The flowrate Q = 0.625 x 10-3 m^3-/s

The diameter of the nozzle d = 5.19 x 10^-3 m

the velocity V = ?

The cross-sectional area of the flow A = $\pi d^{2}/4$

==> (3.142 x 5.19 x 10^-3)/4 = 4.077 x 10^-3 m^2

From the continuity equation,

Q = AV

V = Q/A = (0.625 x 10-3)/(4.077 x 10^-3) = 0.153 m/s

4 0

4 years ago

A toroid having a square cross section, 5.00 cm on a side, and an inner radius of 15.0 cm has 500 turns and carries a current of

SCORPION-xisa [38]

Answer:

a).β=0.53 $x10^{-3}$ T

a).β=0.40 $x10^{-4}$ T

Explanation:

The magnetic field at distance 'r' from the center of toroid is given by:

$\beta =\frac{u_{o}*I*N}{2\pi*r}$

a).

$N=500\\I=0.800A\\r=15cm*\frac{1m}{100cm}=0.15m\\u_{o}=4\pi x10^{-7}\frac{T*m}{A} \\\beta=\frac{4\pi x10^{-7}\frac{T*m}{A}*0.8A*500}{2\pi*0.15m} \\\beta=0.53x10^{-3}T$

b).

The distance is the radius add the cross section so:

$r_{1}=15cm+5cm\\r_{1}=20cm$

$r_{1} =20cm*\frac{1m}{100cm}=0.20m$

$\beta =\frac{u_{o}*I*N}{2\pi*r1}$

$\beta =\frac{4\pi x10^{-7}*0.80A*500 }{2\pi*0.20m} \\\beta=0.4x10^{-3} T$

3 0

4 years ago