coefficient of static friction is 1.7329
Explanation:
given data
velocity = 60 mph
acceleration = 17 m/s²
to find out
coefficient of static friction
solution
we will apply here centripetal force equation
that is
m×v²/r = µ × m × g ..................1
here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so
µ = a / g
µ = 17 / 9.81
µ = 1.7329
so coefficient of static friction is 1.7329
Answer:
appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity
Explanation:
Answer:
<h2>18.51 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>18.51 J</h3>
Hope this helps you
Answer:
Suppose the micrometeoroid weighed 1 g = .001 kg
Suppose also the spacecraft were moving at 18,000 mph (1.5 hrs per rev)
Usually, the smaller particle would be moving but for simplicity suppose that it were stationary wrt the ground
v = 18000 miles / hr * 1500 m/mile / 3600 sec/hr = 7500 m/s
KE = 1/2 * .001 kg * (7500 m)^2 = 28,125 Joules
One can see that 28000 Joules could be damaging amount of energy