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3 years ago

Describe the movement of particles at the melting point of a substance with temperature and energy.

Physics

1 answer:

Gnesinka [82]3 years ago

7 0

Answer:

As a substance reaches the melting point, the particles begin to move faster, causing the substance to become a liquid.

Explanation:

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What is the resistance of the coil A at 600 kelvin if its resistance at 300 kelvin is 50 ohms? (Assume the temperature coefficie

leonid [27]

155Ω

Explanation:

R = R ref ( 1 + ∝ ( T - Tref)

where R = conduction resistance at temperature T

R ref = conductor resistance at reference temperature

∝ = temperature coefficient of resistance for conductor

T = conduction temperature in degrees Celsius

T ref = reference temperature that ∝ is specified at for the conductor material

T = 600 k - 273 k = 327 °C

Tref = 300 - 273 K = 27 °C

R = 50 Ω ( 1 + 0.007 ( 327 - 27) )

R = 155Ω

8 0

3 years ago

Read 2 more answers

Which is not expecting acceleration?

Kamila [148]

1. Answer: A skydiver whose air resistance is equal to that of her weight.

A skydiver free falls under gravity but her rate of fall slows down due to drag -air resistance. when this air resistance becomes equal to her weight, the two get balanced and the body does not accelerate or decelerates.

2. Answer: Gravity

Contact forces are those which act when there is physical contact between two bodies. For example: normal force, tension and spring force.

Non-contact forces act between two bodies even when they are at a distance apart. For example: gravity, electric force, magnetic force etc.

3. Answer: The tendency of an object's motion to remain the same.

Inertia is a property of matter by virtue of which it tends to remain in its state of motion or rest. It does depend on mass of the object, more the mass, more is inertia. For example, cycle can be easily moved but we need real push hard for a car to move.

4. Answer: 254 N

The man pushes the box with 310 N force at an angle of 55 degrees to the horizontal.

we can write this in terms of horizontal ( $F cos \theta$ )and vertical component ( $F sin\theta$ ).

Horizontal component: $F_H=310 \times cos (55^o)= 178 N$

Vertical component: $F_v=310 \times sin (55^o)= 254 N$

The vertical component would act towards the floor making the job more difficult to move the job.

7 0

3 years ago

A 5-m steel beam is lowered by means of two cables unwinding at the same speed from overhead cranes. As the beam approaches the

ArbitrLikvidat [17]

Answer:

a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)

b) The acceleration of point A is 3.25 m/s²

The acceleration of point E is 0.75 m/s²

Explanation:

a) The relative acceleration of B with respect to D is equal:

$a_{B} =a_{D} +(a_{B/D} )_{n} +(a_{B/D} )_{t}$

Where

aB = absolute acceleration of point B = 2.5 j (m/s²)

aD = absolute acceleration of point D = 1.5 j (m/s²)

(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam

(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)

$a_{B} =a_{D} +(a_{B/D} )_{t}$

$2.5j=1.5j +(a_{B/D} )_{t}\\(a_{B/D} )_{t}=j=1m/s^{2}$

We have that

(aB/D)t = BDα

Where α = acceleration of the beam

BDα = 1 m/s²

Where

BD = 2

$2\alpha =1\\\alpha =0.5rad/s^{2}CW$

b) The acceleration of point A is:

$a_{A} =a_{D} +(a_{A/D} )_{t}$

(aA/D)t = ADαj

$a_{A} =a_{D} +AD\alpha j\\a_{A}=1.5j+(3.5*0.5)j\\a_{A}=3.25jm/s^{2}$

The acceleration of point E is:

(aE/D)t = -EDαj

$a_{E} =a_{D} -ED\alpha j\\a_{E}=1.5j-(1.5*0.5)j\\a_{E}=0.75jm/s^{2}$

7 0

3 years ago

the half-life of iodine-131 is 8.1 days. how much time had passed if i only have one-fourth of the original sample?

morpeh [17]

Answer:

16.2 days

Explanation:

Find the number of halflives:

1/2 * 1/2 = 1/4 so <u>two</u> halflives have passed

2 * 8.1 days = 16.2 days

8 0

1 year ago

3. What is the difference between Synthetic Oil, Semi-Syntheic oil (Blend), High milage motor oil, and conventional motor oil?

MariettaO [177]

Answer:

When evaluating synthetic blends, it's helpful to define the terms “synthetic blend” and “semi-synthetic”. Generally speaking, synthetic blends and semi-synthetic refer to the same thing: an oil that uses a combination of conventional and synthetic base oils in its formulation.

Explanation:

6 0

3 years ago