The wavelength is the so-called "fundamental" wavelength, or the "first mode." Thus, the wavelength of the string's vibration is defined by the supports, and has nothing whatsoever to do with mass or elasticity.
Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
Answer:
3.5
Explanation: i divided them
Answer:
e). The ratio is not given
Explanation:
<u>Capacitance of a capacitor</u>
The expression for the capacitance of a capacitor with di electric material is given as
C=KεA/d
where
ε=permittivity of di electric
C= capacitance in farads
A= Area of plate
d= separating distance
K= dielectric constant
let the distance in capacitor B be 1mm
therefore the distance in A is 0.5mm
For the first (A) capacitor
C1=8εA/0.5
C1=16εA
For the Second (B) capacitor
C2=8εA/1
C2=8εA
the ratio of the capacitance of A to B
=C1/C2
=16εA/8εA
=2/1
=2