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Answer:
1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km
2) Mia's average speed is 6.00 km/hour
Peter's average speed is 8.48 km/hour
4) Mia's average velocity = Peter's average velocity = 6.00 km/hour
Explanation:
The given information from the diagram are;
The distance Peter jogs from school to the flower shop = 2.00 km
The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.
The distance Mia walks from school directly to the Coffee shop = 3.00 km
The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour
1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km
The distance Mia travels from school to the Coffee shop = 3.00 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km
2)
Mia's average speed = 6.00 km/hour
Peter's average speed = 8.48 km/hour
4)
The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter
The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour
Mia's average velocity = 6.00 km/hour
Therefore, Peter's average velocity is also = 6.00 km/hour
a) The work done by the tree is
b) The amount of force applied is 2880 N
Explanation:
a)
According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:
where
W is the work done on the car
m is the mass of the car
u is its initial speed
v is its final speed
For the car in this problem, we have:
m = 2000 kg
u = 12.0 m/s
v = 0 (since the car comes to a stop, after the crash)
Therefore, the work done by the tree on the car is:
The work is negative because it is done in the direction opposite to the direction of motion of the car.
b)
The work done by the tree on the car can also be rewritten as
where
F is the force applied on the car
d is the displacement of the car during the collision
In this situation, we have:
is the work done
is the displacement of the car during the collision
Solving the equation for F, we find the force exerted by the tree on the car:
Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.
Learn more about work:
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