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SSSSS [86.1K]
3 years ago
8

VITI How many electrons are in the third energy level?

Physics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

8 (maybe 18)

Explanation:

Depends on whether you have the d orbitals.  If not, it's 8, and it's 18 including the d orbitals

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A 10.0 kg ball weighs 98.0 N in air and weighs 65.0 N when submerged in water. The volume of the ball is:_________.A) 0.00245 m3
Kamila [148]

Answer: B) 0.00337 m3.

Explanation:

Given data:

Mass of the ball = 10kg

Weight of the ball in air = 98N

Weight of the ball in water = 65N

Solution:

To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.

= 98 - 65 / 9.8

= 33 / 9.8

= 3.37kg

The volume of the ball is 3.37kg

The density of water is 1kg per Liter.

So 3.37 kg of water would have a volume of 3.37 Liters.

Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).

7 0
3 years ago
Identify the number of and types of elements in this schematic diagram
Nataly_w [17]
-- The long line and short line close together at the left side
       of the diagram represent a single-cell battery.
It's the only one in this diagram. 
It's a device that stores chemical energy and delivers it on demand.

-- The zig-zag lines with circles around them represent light bulbs.
There are three of them in this diagram. 
They are devices used to produce light by dissipating electrical energy.

-- The zig-zag lines without circles, at the top of the diagram,
       represent resistors.
There are two of them in this diagram.
They are devices used to change or control electrical parameters
   within a circuit by dissipating electrical energy.

-- The short straight line between two small circles at the bottom
       of the diagram  represents a switch.
There is only one switch in this circuit.
It's a device used to easily and quickly start or stop the flow of current
    past a certain point in a circuit.

In this circuit ...

-- When the switch is closed (as drawn), the light bulb nearest the battery
glows brightest, the light bulb in the middle glows less bright, and the light
bulb on the right side glows dimmest of all.

-- When the switch is open, the light bulb nearest the battery glows, and
neither of the other two light bulbs glows at all.
4 0
3 years ago
Read 2 more answers
A circuit consists of an ideal ac generator, a capacitor, and an ideal inductor, all connected in series. The charge on the capa
Serjik [45]

Answer:

-16\omega sin(\omega t + \pi/4)

Explanation:

The function of the current with respect to time is the derivative of the charge function with respect to time t. We can apply chain rule to differentiate it:

I(t) = Q'(t) = (16cos(\omega t + \pi/4))' \\= -16(\omega t + \pi/4)' sin(\omega t + \pi/4) \\= -16\omega sin(\omega t + \pi/4)

7 0
3 years ago
Read 2 more answers
Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di
Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, u=20m/s

And the mass of the car is, m=1000 kg

The total distance covered by the car before stop, s=45m

And the final speed of the car is, u=0m/s

Now initial kinetic energy is,

KE_{i}=\frac{1}{2}mu^{2}

Substitute the value of u and m in the above equation, we get

KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J

Now final kinetic energy is,

KE_{f}=\frac{1}{2}mv^{2}

Substitute the value of v and m in the above equation, we get

KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN

Here, the force is negative because the force and acceleration in the opposite direction.

6 0
3 years ago
A force of 100 N acts upward. Resolve this force into 2 components; one that acts 30º north of west and one that acts 60º north
GrogVix [38]

To resolve these forces we have to make use of the sines and cosines.

To resolve this force in 30 degree north of west, the answer will be

100*sin(30)

The answer will be 50N

Now to resolve the force acting 60 degree north of east

100* cos(60)

The answer will be 50N.

This also adds to the total force acting that is 50+50=100N. This is the way forces are resolved according to their specified angles.

5 0
3 years ago
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