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storchak [24]
1 year ago
13

A stone is dropped from a high cliff vertically. After 6

Physics
1 answer:
bonufazy [111]1 year ago
4 0

Answer:

Ay=v₂t + ½ gt² is the best choice to solve this problem.

The height of the cliff is = 176.4 meters.

Explanation:

Given,

initial velocity = 0m/s as it is dropped vertically

acceleration = g = 9.8 m/s²

time = 6s

Height =?

Using the equation Ay=v₂t + ½ gt², we can calculate Ay, which is the height.

So,

Ay=v₂t + ½ gt²

by substituting v, t, and g, we get:

Ay= 0 × 6 + ½ × 9.8 × 6²

Ay = 0 + 4.9 × 36

Ay = 176.4 m

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Answer:

FALSE!!!

Explanation:

Business letters are formal and normally given to someone of higher importance.

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A weather forecast shows that the humidity will increase to 100% in the next couple of days. How might this affect the weather?I
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This is a question on my physics test :)
Licemer1 [7]

Answer:

119.6 J/Kg°C

Explanation:

Data obtained from the question include:

Mass of substance (ms) = 170 g

Initial temperature of substance (Ts) = 120 °C

Volume of water = 200 mL

Initial temperature of water (Ts) = 10 °C

Temperature of the mixture (T2) = 12.6 °C

Density of water = 1 g/mL

Specific heat capacity of water (Cw) = 4200J/Kg°C

Specific heat capacity of substance (Cs) =..?

Next, we shall determine the mass of water. This can be obtained as follow:

Volume of water = 200 mL

Density of water = 1 g/mL

Mass of water =..?

Density = mass /volume

1 = mass /200

Cross multiply

Mass of water = 1 x 200

Mass of water = 200 g

Convert 200 g of water to Kg

Mass of water = 200/1000 0.2 Kg

Mass of water = 0.2 Kg

Now, we obtained the specific heat capacity of the substance using the following formula:

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

Initial temperature of water (Ts) = 10 °C

Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

Initial temperature of substance (Ts) = 120 °C

Specific heat capacity of substance (Cs) =..?

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

0.2× 4200(12.6 – 10) + 0.17×Cs×(12.6 – 120) = 0

840(2.6) + 0.17Cs(– 107.4) = 0

2184 – 18.258Cs = 0

Rearrange

2184 = 18.258Cs

Divide both side by the coefficient of Cs i.e 18258

Cs = 2184/18.258

Cs = 119.6 J/Kg°C

Therefore, the specific heat capacity of the substance is 119.6 J/Kg°C

7 0
3 years ago
Dinitrogen oxide has?
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The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
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Answer:

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Explanation:

Recall the expression for the continuous exponential growth of a population:

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In our case, we don't know No (original population, but know that we want it to double in a certain elapsed "t". We also have in mind that the percent rate "k" would be expressed in mathematical form as: 0.0024 (mathematical form of the given percent growth rate).

So we need to solve for "t" in the following equation:

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Which can be rounded to about 289 hours

6 0
3 years ago
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