first off lemme just say this is really easy man, just look at the directions
Blank #1: -23
Blank #2: 23
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity, 
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :


I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :


I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :


I = 1688.31 kg-m²
The angular momentum of the system is :



So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.
Answer:

Explanation:
The principle of conservation of momentum, states that if the sum of the forces acting on a system is null, the initial total momentum of the system before a collision equals the final total momentum of the system after the collision. The collision is completely inelastic, which means that the players remain stick to each other after the collision:

Answer:
v₂ = 5.7 m/s
Explanation:
We will apply the law of conservation of momentum here:

where,
Total Initial Momentum = 340 kg.m/s
m₁ = mass of bike
v₁ = final speed of bike = 0 m/s
m₂ = mass of Sheila = 60 kg
v₂ = final speed of Sheila = ?
Therefore,

<u>v₂ = 5.7 m/s </u>
Crates is the correct answer because they create dents that make the bumps of mountains.