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2 years ago

How could the action force of a canoe moving through water be increased?

2 answers:

4 0

One way the action force of a canoe could be increased is by peddling with an oar while sitting in the canoe. The point here is that the oar pushes against the current of the water, causing the canoe to move further.

Gemiola [76]2 years ago

4 0

One way the action force of a canoe could be increased is by peddling with an oar while sitting in the canoe

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Jasper didn't want to help out with the dishes. He put off the task toward the end of the day. He even tried to get his

Temka [501]

Answer:

The last answer work avoident goal

8 0

2 years ago

Wнιcн parт oғ тнe eхaмple repreѕenтѕ heat

PtichkaEL [24]

I would think something like fire or a torch because that seems like it means heat or maybe a campfire picture

3 0

2 years ago

how can there be so many different substances in the world if there are only a few elements that are common?

LuckyWell [14K]

-- If there are only 10 elements in the universe that can make compound molecules, and a compound molecule can be formed by combining 1, 2, 3, or 4 different elements, then that's already the possibility of at least 400 different molecules.

-- There are many more than 10 elements that can combine to form compound molecules.

-- Every single "organic" molecule, of which there are thousands, is the combination of carbon with other elements.

-- Most all of the substances that can be distilled out of oil, including the paraffin waxes, the alcohols, gasoline, kerosene, butane, propane, octane, and natural gas, are made of just carbon, hydrogen, and oxygen, only with different numbers of each one.

-- Plastics, drugs, rubber, and DNA are examples of molecules that are made of hundreds of atoms.

3 0

2 years ago

A 2 eV electron encounters a barrier 5.0 eV high and width a. What is the probability b) 0.5 that it will tunnel through the bar

denis23 [38]

Answer:

The tunnel probability for 0.5 nm and 1.00 nm are $5.45\times10^{-4}$ and $7.74\times10^{-8}$ respectively.

Explanation:

Given that,

Energy E = 2 eV

Barrier V₀= 5.0 eV

Width = 1.00 nm

We need to calculate the value of $\beta$

Using formula of $\beta$

$\beta=\sqrt{\dfrac{2m}{\dfrac{h}{2\pi}}(v_{0}-E)}$

Put the value into the formula

$\beta = \sqrt{\dfrac{2\times9.1\times10^{-31}}{(1.055\times10^{-34})^2}(5.0-2)\times1.6\times10^{-19}}$

$\beta=8.86\times10^{9}$

(a). We need to calculate the tunnel probability for width 0.5 nm

Using formula of tunnel barrier

$T=\dfrac{16E(V_{0}-E)}{V_{0}^2}e^{-2\beta a}$

Put the value into the formula

$T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times0.5\times10^{-9}}$

$T=5.45\times10^{-4}$

(b). We need to calculate the tunnel probability for width 1.00 nm

$T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times1.00\times10^{-9}}$

$T=7.74\times10^{-8}$

Hence, The tunnel probability for 0.5 nm and 1.00 nm are $5.45\times10^{-4}$ and $7.74\times10^{-8}$ respectively.

6 0

3 years ago

Technician A says that the accumulator is on the high-pressure side of the refrigerant system. Technician B says that the receiv

pychu [463]

Question:

The options are

a. Technician A only

b. Technician B only

c. Both A and B

d. Neither A nor B

Answer:

The correct option is

d. Neither A nor B

Explanation:

Here, we note that to locate the receiver/driers we look at the high-pressure side of refrigerant system normally around the tubes in between the expansion valve outlet and the condenser outlet and connected to the condenser.

While the accumulator can be found, attached to the evaporator outlet within the low pressure side of the refrigerant system.

Therefore, neither Technician A nor B is correct.

6 0

2 years ago