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inysia [295]
2 years ago
13

How could the action force of a canoe moving through water be increased?

Physics
2 answers:
____ [38]2 years ago
4 0
One way the action force of a canoe could be increased is by peddling with an oar while sitting in the canoe. The point here is that the oar pushes against the current of the water, causing the canoe to move further.
Gemiola [76]2 years ago
4 0
One way the action force of a canoe could be increased is by peddling with an oar while sitting in the canoe
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A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s
DedPeter [7]

Answer:

212.8 m/s^{2}

Explanation:

Time taken by stone to cover horizontal distance

t=\sqrt{\frac {2h}{g}} where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

t=\sqrt{\frac {2*2.1}{9.81}}= 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

a=\frac {v^{2}}{r} where r is radius of circle, substituting r with 1.1m

a=\frac {15.3^{2}}{1.1}

a=212.8 m/s^{2}

Therefore, centripetal acceleration is 212.8 m/s^{2}

8 0
3 years ago
How might the climate be affected if you were people drove automobiles and more people road bikes or use public transportation l
Hoochie [10]
The level of greenhouse gases in our atmosphere would decrease, due to less automobiles.
8 0
2 years ago
A 2.0 kg block has a rope attached to the block on a table and is pulled with a force of 8.0 N. The block accelerated at 2.5m/s^
Masja [62]

Answer:

0.15

Explanation:

Assuming the rope is horizontal, sum the forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Sum the forces in the x direction:

∑F = ma

F − Nμ = ma

Substitute:

F − mgμ = ma

mgμ = F − ma

μ = (F − ma) / (mg)

Plug in values:

μ = (8.0 N − 2.0 kg × 2.5 m/s²) / (2.0 kg × 9.8 m/s²)

μ = 0.15

3 0
2 years ago
A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances f
sweet-ann [11.9K]

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.

5 0
2 years ago
A circle is 360°. What percentage of a circle is 90°?
kykrilka [37]

Answer:

360 ÷ 4 = 90

Example

A 360° circle is cut into 4 peaces in the form of + or × . It's one side is called 90°

6 0
3 years ago
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