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ohaa [14]
1 year ago
11

PLEASE HELP!!!!

Physics
1 answer:
OLEGan [10]1 year ago
6 0

The story that fits the graph is; he elevator moves up, is stationary for a while, then moves down at a slower rate.

<h3>What is a position time graph?</h3>

The term position time graph shows us how the position of the object is changing with time. The position in this case has to do with the exact point in space where the object can be found. We have here an elevator that could be found at various points.

We now have to turn to the graph and see how the graph can be able to give a description of the motion of the elevator. If we look at the position time graph, it tends to move up and then remain at a point for some time before it moves down.

Based on the analysis that we have made above, we can now look out for any of the stories that fits the description that we have just made here.

Learn more about position time graph:brainly.com/question/13693087

#SPJ1

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Read 2 more answers
Charge of uniform linear density (6.7 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric fiel
ad-work [718]

Thw question is not complete. The complete question is;

Charge of uniform linear density (6.7 nCim) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y = 1.6 m. a. 32 N/C b. 150 NC c 75 N/C d. 49 N/C e. 63 NC

Answer:

Option C: E = 75 N/C

Explanation:

We are given;

Uniform linear density; λ = 6.7 nC/m = 6.7 × 10^(-9) C/m

Distance on the y-axis; d = 1.6 m

Now, the formula for electric field with uniform linear density is given as;

E = λ/(2•π•r•ε_o)

Where;

E is electric field

λ is uniform linear density = 6.7 × 10^(-9) C/m

r is distance = 1.6m

ε_o is a constant = 8.85 × 10^(-12) C²/N.m²

Thus;

E = (6.7 × 10^(-9))/(2π × 1.6 × 8.85 × 10^(-12))

E = 75.31 N/C ≈ 75 N/C

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3 years ago
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