Answer:
Part a)
a = - 8.45 m/s/s
Part b)

Part c)

Explanation:
Part a)
when car apply brakes then the friction force on the car in front of us is given as

here we need to find deceleration due to friction



Part b)
Braking distance of the car is the distance that it move till it stops
so we will have



Part c)
Since we know that average reaction time for human is 0.424 s
now we know that during reaction time our car will travel at uniform speed
so we will have



Answer:
Potential difference will be 151.9 volt
Explanation:
We have given capacitance of the capacitor 
Voltage V = 49 Volt
Dielectric constant K = 3.1
We have to find the potential difference
We know that when a dielectric medium is introduced then p[otential difference is increases by k times
As the dielectric constant k = 3.1
So potential difference will be = 3.1×49 = 151.9 volt
Answer:
Atoms in a element on the periodic table I dont know which one tho so try google that sorry I am not much of a help
Explanation:
Gravitational potential energy is an object that possesses because of its position in a gravitational field
Answer: C. the rod gains mass and the fur loses mass.
Explanation:Atomic particles have mass. The electron has a mass that is approximately 1/1836 that of the proton and with exchange exchange of charge this is also factored in. The movement of effect described above is known as the triboelectic charging process—charging by friction—which results in a transfer of electrons between the two objects when they are rubbed together. Plastic having a much greater affinity for electrons than animal fur pulls electrons from the atoms of fur, leaving both objects with an imbalance of charge. The plastic rod would have an excess of electrons and the fur has a shortage of electrons. Having an excess of electrons, the plastic is charged negatively and has more mass. In the same vein, the shortage of electrons on the fur leaves it with a positive charge and consequently with lesser mass.