For the original solution,
Concentration = 85g/L = 85g/1000ml
Required Volume = 150ml
(a)
Concentration = Mass/Volume
⇒ 85g/1000ml = Mass of the solute/150ml
⇒ Mass of the solute = 85 x 150/1000
⇒ Mass of the solute = 12.75 grams
Hence, 12.75 grams of the solute is required to prepare the original solution.
(b)
Now,
Concentration of the original solution = 85g/L = M1
Required concentration = 50g/L = M2
Final Volume = 500 ml = V2
Required Volume from the original solution = V1 =?
As we know,
M1V1 = M2V2
Hence,
85g/L x V1 = 500 ml x 50g/L
⇒ V1 = 500 X 50 / 85
⇒ V1 = 294.11 ml
Therefore, 294.11 ml of the original solution is required to make the diluted solution.
<h3>What is a Stock solution?</h3>
- A stock solution is a very potent mixture. These solutions are quite helpful since we may take a small amount of the stock solution and dilute it to the required concentration.
- These ready-to-use chemical reagents can be prepared quickly thanks to these stock solutions. It also aids in material conservation.
- As a result, just the amount of stock and solvent required for the dilution process is consumed when utilizing a stock solution to low-concentrated solution.
- Because we simply need to dilute the stock solution instead of preparing the solution using many reagents and complex procedures, it is also crucial to conserve storage space.
- Additionally, it enhances experiment accuracy.
- A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration.
- Examples of typical stock solutions in laboratories are sodium hydroxide and hydrochloric acid. These play a critical role in creating titration-related solution preparations.
To learn more about the Stock solution, refer to:
brainly.com/question/28083950
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