Answer : The correct option is, +91 kJ/mole
Solution :
The balanced cell reaction will be,  

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.
First we have to calculate the standard electrode potential of the cell.
![E^0_{[Pb^{2+}/Pb]}=-0.13V](https://tex.z-dn.net/?f=E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D%3D-0.13V)
![E^0_{[Cu^{2+}/Cu]}=+0.34V](https://tex.z-dn.net/?f=E%5E0_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D%3D%2B0.34V)

![E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}](https://tex.z-dn.net/?f=E%5E0_%7Bcell%7D%3DE%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D-E%5E0_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D)

Now we have to calculate the standard Gibbs free energy.
Formula used :

where,
 = standard Gibbs free energy = ?
n = number of electrons = 2
F = Faraday constant = 96500 C/mole
 = standard e.m.f of cell = -0.47 V
Now put all the given values in this formula, we get the Gibbs free energy.

Therefore, the standard Gibbs free energy is +91 kJ/mole
 
        
             
        
        
        
Answer:
CARBOHYDRATES AND CARBOHYDRATE METABOLISM
 
        
             
        
        
        
Lipid you can look up the chemical structures and lipids are the longest which make them the largest
        
             
        
        
        
<span>ions are solutions containing ions that react with acids or bases to minimize their effects. </span>
        
             
        
        
        
I think it will be D or B but my mine answer is D