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worty [1.4K]
1 year ago
12

calculate the kinetic energy of a 820 kg compact car moving at 23 m/s.

Physics
1 answer:
WARRIOR [948]1 year ago
8 0

Answer:

216,890 J

Explanation:

We first define the Kinetic Energy Formula:

K.E =

\frac{1}{2} m {v}^{2}

where m is the mass of the object in kg, and v is the velocity in m/s.

Given from the information from the question, we substitute the values in to find K.E.

K.E of car =

\frac{1}{2} (820) {(23)}^{2}  \\  = 216890 \: joules

Note that the SI unit for Energy is Joules or J.

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4 years ago
A man standing 1.54 m in front of a shaving mirror produces a real, inverted image 15.2 cm from it. What is the focal length of
zavuch27 [327]

Answer:

The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

Explanation:

Given that,

Object distance u=1.54 m =154 cm

Image distance v = 15.2 cm

Magnification = 2

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{15.2}+\dfrac{1}{-154}

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Using formula of magnification

m= \dfrac{-v}{u}

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2=\dfrac{v}{u}

v = -2u

Using formula of for focal length

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{16.86}=\dfrac{1}{u}-\dfrac{1}{2u}

\dfrac{1}{16.86}=\dfrac{1}{2u}

2u=16.86

u=\dfrac{16.86}{2}

u=8.43\ cm

Hence, The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

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