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worty [1.4K]
1 year ago
12

calculate the kinetic energy of a 820 kg compact car moving at 23 m/s.

Physics
1 answer:
WARRIOR [948]1 year ago
8 0

Answer:

216,890 J

Explanation:

We first define the Kinetic Energy Formula:

K.E =

\frac{1}{2} m {v}^{2}

where m is the mass of the object in kg, and v is the velocity in m/s.

Given from the information from the question, we substitute the values in to find K.E.

K.E of car =

\frac{1}{2} (820) {(23)}^{2}  \\  = 216890 \: joules

Note that the SI unit for Energy is Joules or J.

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Answer:

A. Speed

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7 0
3 years ago
Two buses are driving along parallel freeways that are 5mi apart, one heading east and the other heading west. Assuming that eac
Oksanka [162]

Answer:

101.54m/h

Explanation:

Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;

Let l be the be the distance further away at which they will meet from the current points;

l=\sqrt{13^2-5^2}=12m\\\\\frac{dl}{dt}=-(55m/h+55m/h})\\\\=-110m/h#The speed toward each other.

\frac{dh}{dt}=0, \ \ \ \ h=constant\\\\h^2+l^2=b^2\\\\2h\frac{dh}{dt}+2l\frac{dl}{dt}=2b\frac{db}{dt}\\\\2\times5\times0+2\times12\times(-110)=2\times13\frac{db}{dt}\\\\\frac{db}{dt}=-101.54m/h

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h

4 0
3 years ago
A gas exerts less pressure when it has a
Vika [28.1K]
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert<span> small force on the wall The </span>pressure exerted<span> by the </span>gas<span> is due to the sum of all these collision forces.The more particles that hit the walls, the higher the </span>pressure<span>.</span>
4 0
3 years ago
Convert mm3 into m3.​
bixtya [17]

Answer:

1 \times 10 { - }^{9}

cubic metre or 1e-9

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3 years ago
A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater
Mice21 [21]

Answer:

So, at the depth of 24 cm below the surface of the glycerine the pressure is  2970 Pa. Hence, this is the required solution.

Explanation:

Given that,

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3 years ago
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