<span>Discrimination is illegal, but caste system is legal.
So answer: False</span>
1. Using Strong Permanent. 2. increasing the current. 3. Decreasing the space between Magnets
Explanation:
Brainiest
Answer:
Pressure applied by the man= 285103.125
or 41.35 ![lb/in^{2}](https://tex.z-dn.net/?f=lb%2Fin%5E%7B2%7D)
Explanation:
Pressure is defined as the perpendicular force applied per unit area.
i.e. ![Pressure=\frac{Force}{Area}](https://tex.z-dn.net/?f=Pressure%3D%5Cfrac%7BForce%7D%7BArea%7D)
Now, ![Force= mg](https://tex.z-dn.net/?f=Force%3D%20mg)
where,
= mass of the body(man) = 93 kg
= acceleration due to gravity of Earth = 9.81 ![m/{s^{2}}](https://tex.z-dn.net/?f=m%2F%7Bs%5E%7B2%7D%7D)
covered is equal to the area of both stilts(a man generally stands on two feet)
therefore
![m^{2}](https://tex.z-dn.net/?f=m%5E%7B2%7D)
and putting in the values, we get,
![Pressure=\frac{93\times9.81}{2\times(0.04)^{2}}Nm^{-2}=285103.125Nm^{-2}](https://tex.z-dn.net/?f=Pressure%3D%5Cfrac%7B93%5Ctimes9.81%7D%7B2%5Ctimes%280.04%29%5E%7B2%7D%7DNm%5E%7B-2%7D%3D285103.125Nm%5E%7B-2%7D)
Now we need to convert to our required units:
![1Nm^{-2}=1Pa\\1Pa=0.000145038lb/in^{2}](https://tex.z-dn.net/?f=1Nm%5E%7B-2%7D%3D1Pa%5C%5C1Pa%3D0.000145038lb%2Fin%5E%7B2%7D)
(We can get the above result by individually converting kg to lb and meters to inches respectively)
Using the above relations we get,
![Pressure=285103.125Pa=0.000145038\times285103.125lb/in^{2}=41.35lb/in^{2}](https://tex.z-dn.net/?f=Pressure%3D285103.125Pa%3D0.000145038%5Ctimes285103.125lb%2Fin%5E%7B2%7D%3D41.35lb%2Fin%5E%7B2%7D)
Answer:
Remain the same
Explanation:
There is no relationship between amplitude frequency.
Answer:
The requested distance is 4320 meters
Explanation:
We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:
![v=\frac{distance}{time}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
Since we know the velocity and the time, we can solve for the distance:
![\neq v=\frac{distance}{time} \\18\,\frac{m}{s} = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m](https://tex.z-dn.net/?f=%5Cneq%20v%3D%5Cfrac%7Bdistance%7D%7Btime%7D%20%5C%5C18%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%20%3D%20%5Cfrac%7Bdistance%7D%7B240%5C%2C%5C%2Cs%7D%20%5C%5Cdistance%3D18%5C%2C%2A%5C%2C240%5C%2C%5C%2Cm%5C%5Cdistance%3D%204320%5C%2C%5C%2Cm)