The work done by the force is 47.1 J
Explanation:
The work done by a force in moving an object is given by
(1)
where
F is the magnitude of the force
d is the distance covered by the object
is the angle between the direction of the force and the motion of the object
In this problem, the force applied to the object is
F = 3.0 N
This force is always tangential to the track: this means that at every instant, the force is parallel to the motion of the object, so
And the distance covered is equal to the circumference of the circle, which is:
where r = 2.5 m is the radius.
Now we can substitute into eq.(1) to find the work done:
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Answer:
she should add solute to the solvent
Explanation:
Given data :
Mass of the sodium chloride, = 20.0 g
Concentration of the solution = 10 g/L
Volume of 20.0 g of sodium chloride = 7.50 mL
Now, from the concentration, we can conclude that for 10 g of sodium chloride volume of the solution is 1 L
thus, for 20 g of sodium chloride volume of the solution is 2 L or 2000 mL
also,
Volume of solution = Volume of solute(sodium chloride) + volume of solvent (water)
thus,
2000 mL = 7.5 mL + volume of solvent (water)
or
volume of water = (2000 - 7.5) mL
or
volume of water = 1992.5 mL
or
volume of water = 199.25 L ≈ 199 L
There are 3 significant figures, if that answers the question.
Answer:
Explanation:
The vertical component of the initial velocities are
If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation
So the ratio of the times of the flights is
