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DedPeter [7]
1 year ago
13

technician a says that hydrogen exists by itself in nature. technician b says that hydrogen has better specific energy than foss

il fuels. which technician is correct?
Engineering
1 answer:
Nikitich [7]1 year ago
7 0

Technician b says that hydrogen has better specific energy than fossil fuels. so technician b is correct.

<h3>Does hydrogen have the highest specific energy?</h3>
  • Although hydrogen has the highest energy density per mass of any fuel, it has the lowest energy density per unit volume due to its low ambient temperature density, necessitating the development of new storage technologies with the potential for higher energy density.
  • Hydrogen is utilized as a rocket fuel and in fuel cells to generate power on some spacecraft because it is beneficial as an energy source or fuel due to its high energy content per unit of weight.
  • Since hydrogen has a significantly higher energy content than fossil fuels, less of it is required to carry out any given task.

To learn more about energy refer to:

brainly.com/question/25959744

#SPJ4

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A driver counts 21 other vehicles using 3 EB lanes on one section of I-80 between her rented car and an overpass ahead. It turne
SVEN [57.7K]

Answer:

vehicle density =  28.205 veh/mile

flow rate =  0.909 veh/hr

Explanation:

given data

count n = 21

distance = 0.78 miles

speed = 52 mph

solution

we get here vehicle density that is express as

vehicle density = n ÷ distance    ...............1

vehicle density = ( 21 + 1 )  ÷ 0.78

vehicle density  k =  28.205 veh/mile

and

now we get here flow rate that is express as

flow rate = k × vs    .................2

flow rate = 28.205 × ( 52 × 0.00062 ÷ 1m )

flow rate =  0.909 veh/hr

6 0
3 years ago
Batteries don’t run forever. Why do you think batteries run down?
Marina86 [1]

Because there is no such thing as immortal batteries.

When a battery is connected to a circuit, the charge moves through the circuit, and a chemical reaction occurs inside that separate the charges. The strength of this reaction diminishes over time and the battery eventually dies.

3 0
3 years ago
Read 2 more answers
Adding moisture is the ONLY way to obtain saturated air from unsaturated air. a)-True b) False
Aleksandr [31]

Answer:

The statement is false.

Explanation:

A unsaturated mass of air can become saturated in 3 ways:

1) Adding moisture to the initially unsaturated air till it becomes saturated.

2) Mixing of 2 different air masses initially unsaturated but the mixture becomes saturated.

3) Reducing the temperature of the surrounding so that the capacity to hold moisture of the air mass decreases until it becomes saturated.

7 0
3 years ago
When casting low carbon steel under certain mold conditions, the mold constant in Chvorinov's rule = 4.0 min/cm2. Determine how
Goshia [24]

Answer:

Solidification time is 2.78 min.

Explanation:

Chvorinov's rule states that the solidification time is directly proportional to the square of ratio of total volume to the total surface area of the cast.

Step1

Given:

Chvorinov's rule constant is 4 min/cm².

Length of the rectangular cast is 30 cm.

Width of the rectangular cast is 15 cm.

Thickness of the rectangular cast is 20 mm or 2 cm.

Calculation:

Step2

Volume of the cast is calculated as follows:

V=l\times b\times t

V=30\times15\times2

V = 900 cm³.

Step3

Total surface area is calculated as follows:

A=2(lb+bt+tl)

A=2(30\times15+15\times2+2\times30)

A=1080 cm².

Step4

Time of solidification is calculated as follows:

t=K(\frac{V}{A})^{2}

t=4(\frac{900}{1080})^{2}

t = 2.78 min.

Thus, solidification time is 2.78 min.

5 0
3 years ago
Water flows in a pipeline. At a point in the line where the diameter is 7 in., the velocity is 12 fps and the pressure is 50 psi
PolarNik [594]

Answer:

a)   P₂ = 3219.11 lbf / ft² , b)    P₂ = 721.91 lbf / ft² , c)  P₂ = 5707.31 lbf / ft²

Explanation:

For this exercise we can use the fluid mechanics equations, let's start with the continuity equation, index 1 is for the starting point and index 2 for the end point of the reduction

     A₁ v₁ = A₂ v₂

     v₂ = v₁ A₁ / A₂

The area of ​​a circle is

    A = π r² = π/4  d²

     v₂ = v₁ (d₁ / d₂)²

Let's calculate

    v₂ = 12 (7/3)²

    v₂ = 65 feet / s

Now let's use Bernoulli's equation

     P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

     P₁ - P₂ = ρ g (y₂ –y₁) + ½ ρ (v₂² - v₁²)

Case 1. The pipe is horizontal, so

      y₁ = y₂

      P₁ - P₂ = ½ ρ  (v₂² –v₁²)

      P₂ = P₁ - ½ ρ (v₂² –v₁²)

     ρ = 62.43 lbf / ft³

     P₁ = 50 psi (144 lbf/ ft² / psi) = 7200 lbf / ft²

    P₂ = 7200 - ½ 62.43 / 32 (65² -12²)

    P₂ = 7200 - 3980.89

    P₂ = 3219.11 lbf / ft²

Case 2 vertical pipe with water flow up

        y₂ –y₁ = 40 ft

        P₁ - P₂ = ρ g (y₂ –y₁) + ½ rho (v₂² - v₁²)

        7200 - P₂ = 62.43 (40) + ½ 62.43 / 32 (65 2 - 12 2) =

        P₂ = 7200 - 2497.2 - 3980.89

         P₂ = 721.91 lbf / ft²

Case 3. Vertical water pipe flows down

         y₂ –y₁ = -40

         P₂ = 7200 + 2497.2 - 3980.89

         P₂ = 5707.31 lbf / ft²

3 0
3 years ago
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