1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rasek [7]
3 years ago
15

A rectangular block having dimensions 20 cm X 30 cm X 40 cm is subjected to a hydrostatic stress of -50 kPa (i.e. under compress

ion). Calculate the change in length of each side. Data: Young's modulus of the block E = 600 kPa, Poisson ratio v=0.45.
Engineering
1 answer:
Semenov [28]3 years ago
5 0

Answer:

\Delta a=-0.166 cm

\Delta b=-0.249 cm

\Delta c=-0.332 cm

Explanation:

Given that E=600 KPa

Poisson ratio=0.45

We know that for hydroststic stress ,strain given as

\varepsilon =\dfrac{\sigma}{E}(2\mu -1)

Here given that \sigma =-50 KPa

Now by putting the values

\varepsilon =\dfrac{50}{600}(2\times 0.45 -1)

\varepsilon =-0.00833

Negative sign indicates that dimensions will reduces due to compressive stress

We know that strain given as

\varepsilon =\dfrac{\Delta L}{L}

Lets take a=20 cm,b=30 cm,c=40 cm.

So \Delta a=-0.00833\times 20 cm

\Delta a=-0.166 cm

\Delta b=-0.00833\times 30 cm

\Delta b=-0.249 cm

\Delta c=-0.00833\times 40 cm

\Delta c=-0.332 cm

You might be interested in
The design for a new cementless hip implant is to be studied using an instrumented implant and a fixed simulated femur.
OlgaM077 [116]

Answer:

a) the velocity of the implant immediately after impact is 20 m/s

b) the average resistance of the implant is 40000 N

Explanation:

a) The impulse momentum is:

mv1 + ∑Imp(1---->2) = mv2

According the exercise:

v1=0

∑Imp(1---->2) = F(t2-t1)

m=0.2 kg

Replacing:

0+F(t_{2} -t_{1} )=0.2v_{2}

if F=2 kN and t2-t1=2x10^-3 s. Replacing

0+2x10^{-3} (2x10^{-3} )=0.2v_{2} \\v_{2} =\frac{4}{0.2} =20m/s

b) Work and energy in the system is:

T2 - U(2----->3) = T3

where T2 and T3 are the kinetic energy and U(2----->3) is the work.

T_{2} =\frac{1}{2} mv_{2}^{2}  \\T_{3} =0\\U_{2---3} =-F_{res} x

Replacing:

\frac{1}{2} *0.2*20^{2} -F_{res} *0.001=0\\F_{res} =40000N

3 0
3 years ago
Water is the working fluid in a Rankine cycle. Superheated vapor enters the turbine at 8 MPa, 560°C and the turbine exit pressur
hoa [83]

Answer:

1. The net power developed=9370.773KW

2. Thermal Efficiency= 0.058

Explanation

Check attachment

5 0
3 years ago
Witch measuring tool would be used to determine the diameter of a crankshaft journal
djverab [1.8K]
Answer =

dial bore gauge

a “dial bore gauge” measures the inside of round holes, such as the bearing journals . can mesure up to 2” and 6” diameter holes .

when ( “ ) is next to a number it means inches fwi - but hope this helped have a good day :)
3 0
2 years ago
The 40-ft-long A-36 steel rails on a train track are laid with a small gap between them to allow for thermal expansion. Determin
vfiekz [6]

Answer:

Ф = 0.02838 ft

F  = 1,032 N

Explanation:

To find out gap delta,

As it is case of free thermal expansion,

First we start with, some assumptions we have to made to solve this problem.

1. Thermal Expansion Coefficient of Steel is ∝= 6.45 ×10^(-6)

2. Modulas of elasticity for A-36 steel is E= 200 GPa

3. Area of rail is assumed to be unit area.

The gape required can be given by,

Ф = ∝  × ΔT  × L  ... where Ф= Gap Delta in ft

                                          ΔT= Temperature rise in F

                                               = 90- (-20)

                                               =  110 F

Ф =  6.45 ×10^(-6) × 110 × 40

Ф =  28,380 × 10^(-6) ft

Ф = 0.02838 ft     .... total gape required for expansion of steel rails

Stress induced in rails is given by,

   σ     =  ∝  × ΔT  × E

          =  6.45 ×10^(-6)   × 110  × 200

  σ      =  1,41,900 Pa

Now, let's find axial force in rails,

Here,we have to consider  ΔT= 20 F.

As due to temperature change, axial force generated in rails can be find by,

F = A × ∝ × ΔT× E × L

F = 1 × 6.45 × 10^(-6) × 20 × 200 × 10^(-9) × 40

F = 25,800 × 40 × 10^(-3)

F = 10,32,000 × 10^(-3)

F= 1,032 N

Finally, due to temperature change, rail is subjected to axial force, axial stress.

8 0
3 years ago
A mass of 5 kg of saturated liquid-vapor mixture of water is contained in a piston-cylinder device at 125 kPa. Initially, 2 kg o
arlik [135]
A because it is the best one
5 0
3 years ago
Other questions:
  • The ratio of the weight of a substance to the weight of equal volume of water is known as a) Density b) specific gravity c) spec
    8·1 answer
  • Three return steam lines in a chemical processing plan enter a collection tank operating at a steady state at 1 bar. Steam enter
    11·1 answer
  • Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print
    10·1 answer
  • The acceleration of a point is given. a = 20 t m/s2 When t=0, s = 50 m and v = -8 m/s. What are the position and velocity of the
    13·1 answer
  • The rainfall rate in a certain city is 20 inches per year over an infiltration area that covers 33000 acres. Twenty percent of t
    6·1 answer
  • Realize the function f(a, b, c, d, e) = Σ m(6, 7, 9, 11, 12, 13, 16, 17, 18, 20, 21, 23, 25, 28)using a 16-to-1 MUX with control
    13·1 answer
  • How do people eat with there noses shut
    12·2 answers
  • Good Morning. Can you help me on this question please?
    5·2 answers
  • How do Geothermal plowerplants relate to engineering?
    11·1 answer
  • Technician A that shielding gas nozzles may have different shapes. Technician B says that gelding gas nozzles is attached to the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!