2. A trapezoidal channel has a bottom width of 4 m and side slopes of 2:1 (H:V). If the flow rate is 50 m3/s at a depth of 3.6 m
1 answer:
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Answer:
The correct response will be "0.992". The further explanation to the following question is given below.
Explanation:
The probability that paging would be beneficial becomes 0.8
Effective paging at the very first attempted is 0.8
On the second attempt the success probability will be:
⇒
⇒
On the third attempt the success probability will be:
⇒
⇒
So that the success probability will be:
⇒
⇒
The pressure difference across the sensor housing will be "95 kPa".
According to the question, the values are:
Altitude,
- 9874
Speed,
- 1567 kph
Pressure,
- 122 kPa
The temperature will be:
→
→
→
now,
→
→
hence,
→ The pressure differential will be:
=
=
Thus the above solution is correct.
Learn more about pressure difference here:
Answer:
A.) Find the answer in the explanation
B.) Ua = 7.33 m/s , Vb = 7.73 m/s
C.) Impulse = 17.6 Ns
D.) 49%
Explanation:
Let Ua = initial velocity of the rod A
Ub = initial velocity of the rod B
Va = final velocity of the rod A
Vb = final velocity of the rod B
Ma = mass of rod A
Mb = mass of rod B
Given that
Ma = 2kg
Mb = 1kg
Ub = 3 m/s
Va = 0
e = restitution coefficient = 0.65
The general expression for the velocities of the two rods after impact will be achieved by considering the conservation of linear momentum.
Please find the attached files for the solution
