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Alekssandra [29.7K]
3 years ago
6

technician a uses a current output test to check ac generator output. technician b uses a voltage output test to check output. w

ho is correct?
Engineering
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

both

Explanation:

Both the technician are correct, ac generator output can be tested in both ways. The two ways are  current output test to check ac generator output. and  voltage output test to check output.

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nikklg [1K]

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I dont know the answer either

Explanation:

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The four important principles of flight are lift, drag, thrust, and _____.
lbvjy [14]

Answer:

gravity force or weight

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A stainless steel ball (=8055 kg/m3, Cp= 480 J/kgK) of diameter D =15 cm is removed from theoven at a uniform temperature of 3
aleksandrvk [35]

Answer:

i) 25.04 W/m^2 .k

ii) 23.82 minutes = 1429.2 secs

Explanation:

Given data:

Diameter of steel ball = 15 cm

uniform temperature = 350°C

p = 8055 kg/m^3

Cp = 480 J/kg.k

surface temp of ball drops to  250°C

average surface temperature = ( 350 + 250 ) / 2 = 300°C

<u>i) Determine the average convection heat transfer coefficient during the cooling process</u>

<em>Note : Obtain the properties of air at 1 atm at average film temp of 30°C from the table  " properties of air "  contained in your textbook</em>

average convection heat transfer coefficient = 25.04 W/m^2 .k

<u>ii) Determine how long this process has taken </u>

Time taken by the process = 23.82 minutes = 1429.2 seconds

Δt = Qtotal / Qavg = 683232 / 477.92 = 1429.59 secs

attached below is the detailed solution of the given question

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Does anyone know obamas last name???? please help its for a friend I swear!!!111!!11!
ANTONII [103]

Answer:

Explanation:

Barack Hussein Obama

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Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2
MatroZZZ [7]

Answer:

Entropy generation==0.12 KW/K

Explanation:

s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}

s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}

s_2-s_1=0.0412\frac{KJ}{kg-K}

Mass flow rate= \rho\times\dfrac{\pi}{4}d^2V

\rho_1=\dfrac {P_1}{RT_1}

\rho_1=\dfrac {240}{0.2598\times 293}

\rho_1=3.51\frac{kg}{m^3}

mass flow rate=\rho_1A_1V_1

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

                                    =0.12 KW/K

8 0
4 years ago
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