just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
B. because jk and cb are on the same spot
Answer: n=-7
Step-by-step explanation:
3n-7=6n-2n
3n-7=4n
-7=n
n=-7
Answer:
Let d be the remaining distance.
Let t be the remaining time.
The standard distance equation is:
d = rt
We are given the rate as 2, so:
d = 2t
At the start of the walk, the remaining distance is 3 miles.
The remaining time is 1.5 hours.
At the end of the walk, the remaining distance is 0 miles.
The remaining time is 0 hours.
A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.
Answer:
The graph of this would be a solid line
