Number of tacos sold is 65 and number of burritos sold is 40
<h3><u>Solution:</u></h3>
Given that Aiden sells each taco for $4.75 and each burrito for $7
Let the number of tacos sold be "t" and number of burritos sold be "b"
Given that Aiden sold 25 more tacos than burritos
t = b + 25 ---- eqn 1
Also given that yesterday Aiden made a total of $588.75 in revenue
number of tacos sold x cost of each tacos + number of burritos sold x cost of each burritos = 588.75

4.75t + 7b = 588.75 ----- eqn 2
Substitute eqn 1 in eqn 2
4.75(b + 25) + 7b = 588.75
4.75b + 118.75 + 7b = 588.75
11.75b = 470
b = 40
Substitute b = 40 in eqn 1
t = 40 + 25
t = 65
Thus the number of tacos sold is 65 and number of burritos sold is 40
The answer is 10.4 because you multiply 0.2 by 52
Answer:
The probability that they will both break down would be 8%
Step-by-step explanation:
I believe it is 8% (sorry if its wrong) because tractor 1 is 3% and tractor 2 is 5% add them together and that is where you get 8%
First you must distribute the 1/4 to get
: 1/2x^2-3=15
then you have to add three to both sides so it become
: 1/2x^2=18
then divide by 1/2 to get
:x^2 =36
then take the square root to get a final answer of
:x=6
x^2 - 9 = (x + 3)(x -3)
3x - 9 = 3(x - 3)
and
6
Common denominator would be 6(x+3)(x - 3)
Answer: 6(x+3)(x - 3)