Nitrogen dioxide is one of the primary components of air pollution. It is released by the combustion of nitrogen oxide.
<h3 /><h3>How do you calculate the percentage yield of nitrogen oxide?</h3>
Given:
- Mass of nitrogen oxide consumed = 1500 kg
- Mass of nitrogen oxide produced = 1500 kg
The given chemical equation of nitrogen oxide is:
Now, to calculate the percentage yield, the following conversion factor should be used:
Nitrogen dioxide = 2300 kg
The percentage yield will be:
Percentage yield = 65.2 %
Thus, the percentage yield of nitrogen dioxide is 65.2%.
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brainly.com/question/9352001
Answer:
3.2 g O₂
Explanation:
To find the mass of O₂, you need to (1) convert grams H₂O to moles H₂O (via molar mass), then (2) convert moles H₂O to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given value (3.6 g).
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂O -----> 2 H₂ + 1 O₂
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
3.6 g H₂O 1 mole 1 mole O₂ 31.996 g
---------------- x --------------- x --------------------- x --------------- = 3.2 g O₂
18.014 g 2 moles H₂O 1 mole
B. No since rusting is a chemical change it does not follow the law of conservation of mass.