Answer:
10.4 m/s
Explanation:
The problem can be solved by using the following SUVAT equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the diver in the problem, we have:
is the initial velocity (positive because it is upward)
is the acceleration of gravity (negative because it is downward)
By substituting t = 1.7 s, we find the velocity when the diver reaches the water:
![v=+6.3 + (-9.8)(1.7)=-10.4 m/s](https://tex.z-dn.net/?f=v%3D%2B6.3%20%2B%20%28-9.8%29%281.7%29%3D-10.4%20m%2Fs)
And the negative sign means that the direction is downward: so, the speed is 10.4 m/s.
50 strands is the standard procedure
'C' is a simple explanation of astigmatism.
The instantaneous velocity always tangential to circular path and instantaneous acceleration always points towards the center of circle.
What is instantaneous?
The definition of instantaneous velocity is the rate of change of location during a time that is virtually zero .The replica was. The definition of instantaneous velocity is the speed of a moving item at a certain instant in time.
The rate of change of location during a relatively brief period of time is known as instantaneous velocity.
In the limit when the time (and thus the displacement) between the two places approaches zero, the instantaneous acceleration is the average acceleration between two points on the route.
so, both of them are perpendicular to each other.
To learn about instantaneous velocity
brainly.com/question/1222392
#SPJ4
Answer: ![-5013.65\ J](https://tex.z-dn.net/?f=-5013.65%5C%20J)
Explanation:
Given
No of moles ![n=3](https://tex.z-dn.net/?f=n%3D3)
Temperature ![T=290\ K](https://tex.z-dn.net/?f=T%3D290%5C%20K)
Initial volume ![V_1=2\ m^3](https://tex.z-dn.net/?f=V_1%3D2%5C%20m%5E3)
Final volume ![V_2=1\ m^3](https://tex.z-dn.net/?f=V_2%3D1%5C%20m%5E3)
Work done in constant temperature process is
![W=nRT\ln \left(\dfrac{V_2}{V_1}\right)](https://tex.z-dn.net/?f=W%3DnRT%5Cln%20%5Cleft%28%5Cdfrac%7BV_2%7D%7BV_1%7D%5Cright%29)
Insert the values
![\Rightarrow W=3\times 8.314\times 290\ln \left (\dfrac{1}{2}\right)\\\\\Rightarrow W=-870\times 8.314\times \ln (2)\\\Rightarrow W=-5013.65\ J](https://tex.z-dn.net/?f=%5CRightarrow%20W%3D3%5Ctimes%208.314%5Ctimes%20290%5Cln%20%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%5C%5C%5C%5C%5CRightarrow%20W%3D-870%5Ctimes%208.314%5Ctimes%20%5Cln%20%282%29%5C%5C%5CRightarrow%20W%3D-5013.65%5C%20J)