We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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Answer:
a.3Hz
b.0.0034m
Explanation:
First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.
The formula relating the length and he frequency is giving as
.
a.we first determine the length of the flute at the fundamental frequency i.e when <em>n</em>=1 and when the speed is in the 342m/s
Hence from
.
since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.
Hence the require beat is
.
b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s
using the formula
Now to determine the extension,
Answer: The correct answer is "Number of rope segments supporting the load".
Explanation:
Mechanical advantage: It is defined as the ratio of the force produced by a machine to the force applied on the machine. The ideal mechanical advantage of a machines is mechanical advantage in the absence of friction.
The ideal mechanical advantage of a pulley system is equal to the number of rope segments which is supporting the load. More the rope segments, It is more helpful to do the lifting the work.
It means that less force is needed for this task to complete.
Therefore, the correct option is (C).
d=? v=2.5 u=0 and t=5 therefore the formula to be used to find the distance my brother covered is d=1/2(v-u)t
d=1/2(2.5-0)5
=6.15m
Answer:
9.875
Explanation:
w=f×s
395=40×s
make s the subject of the formula
s=395/40
=9.875
