The magnitudes of forces at F₁ and F₂ are :
F₁ = 3924 N
F₂ = 4120.2 N
We know that force is the amount of strength required to move a body. The magnitude of force is the sum of all the strengths applied on the body which is exerted by each force together on a particular body.
Given,
Length of plank = 2 m
Force on one end = F₁
Force on the other end = F₂
F₂ is applied to a point which is 0.5 m from the other end
Mass of plank = 20 kg.
Now let us calculate the magnitudes of the forces applied:-
1) Balance of angular momentum around the end where F₁ is applied.
F₂ × 0.5m - F₁ × 0 = mass × g × 1m
⇒ F₂ × 0.5 m= 20 kg × 9.81 m/s² × 1 m = 1,962 N×m
F₂ = 196.2 Nm / 0.5m = 3,924 N
2) Balance of forces
F₁ - F₂ = mg
F₁ = F₂ + mg = 3,924N + 20kg (9.81 m/s²) = 4,120.2 N
Therefore the magnitude of force F₁ is 3924 N and of force F₂ is 4120.2 N.
To know more about force, refer: brainly.com/question/13191643
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