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Daniel [21]
2 years ago
8

Three compounds containing potassium and oxygen are compared. Analysis shows that for each 1.00g of o, the compounds have 1.22g,

2.44, and 4.89 g og K, respectively. Show how this data supports the law of constant composition
Chemistry
1 answer:
Reika [66]2 years ago
7 0

According to the law of constant composition;

  • the first compound, the constant mass ratio of O to K is 1 : 1.22
  • the second compound, the constant mass ratio of O to K = 1 : 2.44
  • the third compound, the constant mass ratio of O to K = 1 : 4.88

<h3>What is the law of constant composition?</h3>

The law of constant composition states that pure samples of a given compound contain the same element combined in the same ratio by mass.

The law is seen practically in that given a compound such as water, all pure samples of water irrespective if the source contains hydrogen and oxygen i a mass ratio of 2 : 1.

Considering the compounds containing potassium and oxygen:

Analysis shows that for each 1.00g of O, the compounds have 1.22g, 2.44, and 4.89 g of K, respectively.

For the first compound, the ratio of mass ratio of O to K = 1 : 1.22

For the second compound, the ratio of mass ratio of O to K = 1 : 2.44

For the third compound, the ratio of mass ratio of O to K = 1 : 4.88

Therefore, this data  supports the law of constant composition.

Learn more about law of constant composition at: brainly.com/question/13808296

#SPJ1

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\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}

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