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beks73 [17]
1 year ago
8

b. science-fiction films sometimes show starships being buffeted by turbulence as they fly through gas clouds such as the lagoon

nebula. does this seem realistic? why or why not?
Physics
1 answer:
Trava [24]1 year ago
5 0

A hydrogen gas cloud 3900 light-years away from the earth is called the Lagoon Nebula . Due to its high temperature of 7500 K, the cloud, which has a diameter of around 45 light-years, glows.

<h3>When flying over turbulence, is it safe?</h3>

The most crucial fact is that turbulence is not dangerous. Despite the discomfort, your plane is designed to withstand the worst. Your aircraft isn't moving near as much as you might believe, even in the worst turbulence!

<h3>What occurs in turbulence?</h3>

When an airplane flies through erratic or ferocious air waves, it creates turbulence. As a result, the aircraft will yaw, pitch, or roll as it moves through the air. Turbulence can be compared to the collision of two oceans.

To know more about Lagoon Nebula visit :-

brainly.com/question/2135790

#SPJ4

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Which of the following is equal to 1W?<br><br>A.1 J<br>B.1 J/s<br>C.1 J·s<br>D.1 N·m
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B. Extra text to get to 20 characters.
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3 years ago
Milk containing 3.7% fat and 12.8% total solids is to be evaporated to produce a product containing 7.9% fat. What is the yield
ratelena [41]

Answer:

the yield of product is YP=46.835 % and the concentration of solids is

Cs = 27.33%

Explanation:

Assuming that all the solids and fats remains in the milk after the evaporation, then the mass of product mP will be

Mass of fat in 100 kg of milk = 100 kg* 0.037 = mP* 0.079

mP = 100 kg* 0.037/0.079  =  46.835 kg

then the yield YP of the product is

YP= mP / 100 kg =  46.835 kg / 100 kg = 46.835 %

YP= 46.835 %

the concentration of solids Cs is

Mass of solids in 100 kg of milk = 100 kg* 0.128 = 46.835 kg * Cs

Cs = 100 kg* 0.128 / 46.835 kg  = 0.2733 = 27.33%

Cs = 27.33%

3 0
3 years ago
As 390 g of hot milk cools in a mug it transfers 30 000 j of heat to the environment. whats is the temperature change of the mil
Fed [463]
You have to use the specific heat equation. 

Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.

So we can substitute our variables into the equation.

30000J = (390g)(3.9J*g/C)ΔT

Solving for ΔT, we get:

30000J/[(390g)*(3.9J*g/C) = ΔT

ΔT = 19.72386588C

I'm assuming the temperature is C, since it was not specified.

Hope this helps!
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<em>Infrared telescope and camera</em>

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An infrared telescope uses infrared light to detect celestial bodies. The infrared radiation is one of the known forms of electromagnetic radiation. Infrared radiation is given off by a body possessing some form of heat. All bodies above the absolute zero temperature in the universe radiates some form of heat, which can then be detected by an infrared telescope, and infrared radiation can be used to study or look into a system that is void of detectable visible light.

Stars are celestial bodies that are constantly radiating heat. In order to see a clearer picture of the these bodies, <em>Infrared images is better used, since they are able to penetrate the surrounding clouds of dust,</em> and have located many more stellar components than any other types of telescope, especially in dusty regions of star clusters like the Trapezium cluster.

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