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gladu [14]
3 years ago
6

A light wave has a 670 {\rm nm} wavelength in air. Its wavelength in a transparent solid is420 {\rm nm} .a)What is the speed of

light in this solid?b)What is the light's frequency in the solid?
Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

Explanation:

given,

Light wave wavelength in Air, λ_(vac) = 670 nm

wavelength in transparent solid, λ= 420 nm

Refractive index of the solid

n = \dfrac{\lambda_{vac}}{\lambda}

n = \dfrac{670}{420}

   n = 1.6

a) speed of light in the solid

v = \dfrac{c}{n}

v = \dfrac{c}{1.6}

       v = 0.625 c

b) light's frequency in the solid

  f = \dfrac{c}{\lambda_{vac}}

frequency of light remain same when light move from one medium to another.

 f is the frequency of light

  f = \dfrac{3\times 10^8}{670\times 10^{-9}}

        f = 4.47 x 10⁻¹⁴ Hz

the light's frequency in the solid is equal to 4.47 x 10⁻¹⁴ Hz

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Fudgin [204]

Answer:

A. 0.25 A

B. 4.5 V

Explanation:

A. The total resistance of resistances in series is:

R = R₁ + R₂

R = 18 Ω + 18 Ω

R = 36 Ω

Ohm's law:

V = IR

9 V = I (36 Ω)

I = 0.25 A

B. The voltage across the bulb (between P and the battery) can be found with Ohm's law.

V = IR

V = (0.25 A) (18 Ω)

V = 4.5 V

3 0
3 years ago
A man pushed the box with a force of 20 N. The mass of the box doubled, but he still pushed with a force of 20 N.
Nuetrik [128]

Answer:

Option (c) Acceleration is 1/2x the original acceleration

Explanation:

To know the the correct answer to the question, we shall determine the acceleration of the box in each case.

Case 1:

Mass (m) = m

Force (F) = 20 N

Acceleration 1 (a₁) =?

F = ma₁

20 = m × a₁

Divide both side by m

a₁ = 20 / m

Case 2:

Mass (m) = 2m

Force (F) = 20 N

Acceleration 2 (a₂) =?

F = ma₂

20 = 2m × a₂

Divide both side by 2m

a₂ = 20 / 2m

a₂ = 10 / m

Finally, we shall determine the acceleration of the box after the mass was doubled. This can be obtained as illustrated below:

Acceleration 1 (a₁) = 20 / m

Acceleration 2 (a₂) = 10 / m

a₂ : a₁ = 10 / m : 20 / m

a₂ / a₁ = 10 / m ÷ 20 / m

a₂ / a₁ = (10 / m) × (m / 20)

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

Thus, the acceleration of the box after the mass was doubled is ½ times the original acceleration.

7 0
2 years ago
A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?
bezimeni [28]

Answer:

45 J

Explanation:

The equation for work is:

Work=Force*Distance

We can substitute the given values into the equation:

Work=15N*3m\\Work=45Nm\\Work=45J

7 0
2 years ago
Read 2 more answers
during a journey, a car travels at 40 km in 2.5 hours, next 62 km in 3 hours, then took a break for 30 minutes, again travelled
wlad13 [49]
45mph is the answer if you do the math right
6 0
3 years ago
Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number
NemiM [27]

Answer:

The height of the tree is three (3) deep

Explanation:

It's 3 deep

Under 129, comes 125 and 685;

Under 125, comes 52 : Under 685, comes 511;

Under 52, comes 46 : Under 511, is 601.

This is illustrated below.

129

∧

125,685

|,|

52,511

|,|

46,601

5 0
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