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gladu [14]
3 years ago
6

A light wave has a 670 {\rm nm} wavelength in air. Its wavelength in a transparent solid is420 {\rm nm} .a)What is the speed of

light in this solid?b)What is the light's frequency in the solid?
Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

Explanation:

given,

Light wave wavelength in Air, λ_(vac) = 670 nm

wavelength in transparent solid, λ= 420 nm

Refractive index of the solid

n = \dfrac{\lambda_{vac}}{\lambda}

n = \dfrac{670}{420}

   n = 1.6

a) speed of light in the solid

v = \dfrac{c}{n}

v = \dfrac{c}{1.6}

       v = 0.625 c

b) light's frequency in the solid

  f = \dfrac{c}{\lambda_{vac}}

frequency of light remain same when light move from one medium to another.

 f is the frequency of light

  f = \dfrac{3\times 10^8}{670\times 10^{-9}}

        f = 4.47 x 10⁻¹⁴ Hz

the light's frequency in the solid is equal to 4.47 x 10⁻¹⁴ Hz

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A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
valina [46]

Answer:

They will meet at a distance of 7.57 m

Given:

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Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

h = ut + \frac{1}{2}gt^{2}

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t = 0.707 s

Now,

When the policeman was chasing across:

d_{x} = u_{x}t + \frac{1}{2}gt^{2}

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Ymorist [56]

Answer:

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Explanation:

Angle of incident and angle of reflection is same.

tan Θh = L' / x (eye)

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x (eye) = Distance of the mirror from the eye

tan Θh = L / (x (eye) + xw)

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