The EPA requires treated tap water<span> to have a detectable </span>level of chlorine<span> to help prevent contamination. The allowable </span>chlorine <span>in </span>drinking water<span> (up to 4 parts per million) pose “no known or expected health risk [including] an adequate margin of safety.”</span>
Paramecium<span> can be found in aquatic environments, usually in stagnant, warm water.</span>
Answer: 71.93 *10^3 N/C
Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:
∫E*dr=Q inside/εo Q inside is given by: λ*L then,
E*2*π*r*L=λ*L/εo
E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C
Answer:
Differences between freefall and weightlessness are as follows:
<h3>
<u>Freefall</u></h3>
- When a body falls only under the influence of gravity, it is called free fall.
- Freefall is not possible in absence of gravity.
- A body falling in a vacuum is an example of free fall.
<h3>
<u>Weightlessness</u></h3>
- Weightlessness is a condition at which the apparent weight of body becomes zero.
- Weightlessness is possible in absence of gravity.
- A man in a free falling lift is an example of weightlessness.
Hope this helps....
Good luck on your assignment....
The force constant is 2.145 N/m.
<h3>What is spring constant?</h3>
- The spring constant is the force required to stretch or compress a spring divided by the distance traveled by the spring. It is used to determine whether a spring is stable or unstable.
- K is the proportionality constant, also known as the 'spring constant.' Hooke's law (F = -kx) specifies stiffness and strength via the k variable. The greater the value of k, the greater the force required to stretch an object to a given length.
Using the relation;
T = 2π√m/k
T = time period = 0.45 s
m = mass of object in kilograms = 0.011kg
k = spring constant
To find k based on the formula,
k = 4 × (3.142)^2 × 0.011 / (0.45 )^2
k = 2.145 N/m
Therefore the force constant is 2.145 N/m.
To learn more about force refer to :
brainly.com/question/12785175
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