a car goes from a velocity zero to a velocity of 15 meters per second East in 2.1 seconds. What is the car's acceleration?
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Answer:
300N
Explanation:
Given parameters:
Mass of car = 1500kg
Initial velocity = 0m/s
Distance covered = 45m
Time = 15s
Unknown:
Net force applied = ?
Solution:
From Newton's second law:
Force = mass x acceleration
Force = mass x
v is the final velocity
u is the initial velocity
t is the time taken
Final velocity = =3m/s
Force = 1500 x = 300N
By using Coulomb's law, we want to find the value of q₁ given that q₂ experiences no net electric force. We will find that q₁ = 8nC
<h3>Working with Coulomb's law.</h3>Coulomb's law says that for two charges q₁ and q₂ separated by a distance r, the force that each one experiences is:
Where k is a constant
Here we can see that q₂ interacts with two charges, then the total force on q₂ will be:
And we know that it must be equal to zero, so we can write it as:
The parenthesis must be equal to zero, so we can write:
And now we can solve this for q₁ to get:
If you want to learn more about Coulomb's law, you can read: