For q3 to be in equilibrium the total force acting on it has to be zero.
Let's say that total distance traveled by car is L (this is just for the convenience).
We can set up a system of equations to find an answer. Let's say that from q1 to q3 the distance is r_1 and from q3 to q2 the distance is r_2, we know that this distance has to be equal to:

The second equation is going to the total force acting on the charge q3:

k_c is the Coulomb's constant. Since left-hand side is zero we just divide whole equation with k_c to get rid of it:

Let's solve this for r_1^2:

Now we have a quadratic equation with following parameter:

We know that two solutions are:

We need a positive solution. When we plug in all the numbers we get:
<span><span> High School </span> <span> Physics </span> <span> 5+3 pts </span> </span><span><span>Previous question </span> </span> <span><span>Next question </span> </span> <span>Naomi wants to know the effect of different colors of light on the growth of plants. She believes that plants can survive best in white light. She buys 25
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Helium... from the greek word helios... the sun
<span>selenium... from the greek word selene... the moon </span>
<span>palladium.. after the asteroid pallas </span>
<span>tellurium...from the greek word tellus... the earth </span>
<span>mercury...after the planet mercury </span>
<span>cerium... after the asteroid ceres </span>
<span>uranium...after the planet uranus </span>
<span>neptunium.. after the planet neptune </span>
<span>plutonium.. after the planet pluto</span>
The correct answer for this question is this one: "The drops dripped from a bloody knife about 2 ft above the ground."
<span>On a floor directly underneath a second-floor balcony, there are several spherical drops of blood about 7 mm in diameter. The statement that best accounts for the drops is that <em>the </em></span><span><em>drops dripped from a bloody knife about 2 ft above the ground.</em>
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Hope this helps answer your question and have a nice day ahead.
The coefficient of expansion is 13 * 10^-6 m per meter length.per oK
The temperature difference = 42 - - 8 = 50 oC
delta T = (42 + 273) - (-8 + 273) = 50 oK
delta L = L * 13* 10^6 m/oK
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m