I’m not entirely sure tbh
Answer:
the thermal energy generated in the loop = 
Explanation:
Given that;
The length of the copper wire L = 0.614 m
Radius of the loop r = 
r = 
r = 0.0977 m
However , the area of the loop is :



Change in the magnetic field is 
Then the induced emf e = 
e = 
e = 2.74 × 10⁻³ V
resistivity of the copper wire
Ω m
diameter of the wire = 1.08 mm
radius of the wire = 0.54 mm = 0.54 × 10⁻³ m
Thus, the resistance of the wire R = 
R = 
R = 1.13× 10⁻² Ω
Finally, the thermal energy generated in the loop (i.e the power) = 
= 
= 
Answer:11.59 J
Explanation:
Given
mass of Particle 
Initially Particle moves towards left 
Final velocity of Particle is towards Right 
According to Work Energy theorem
Work done by all the Forces=change in Kinetic Energy
Work done by Force
![W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%2031%5E-25%5E2%5Cright%20%5D)
![W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%20961-625%5Cright%20%5D)
