F(x)=x^2-12x+20 a. f(0) = ? b. f(2) = ? c. f(x) = 0,x = ? d. f(x)= 9,x = ?

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

7 0

3 years ago

Donny's charge account statement showed a previous balance of $765.98, a finance charge of $7.50, new purchases of $97.50 and $3

nataly862011 [7]

I think the answer is 345.75

hope this helps

5 0

3 years ago

Read 2 more answers

The graph of an absolute value function has a vertex of (2,3) and crosses the x-axis at (−1,0) and (5,0). What is the equation f

frez [133]

Answer:

Option D.

Step-by-step explanation:

The vertex form of an absolute function is

$y=a|x-h|+k$

where, a is a constant, (h,k) is vertex.

It is given that, vertex of an absolute function is (2,3). So, h=2 and k=3.

$y=a|x-2|+3$ ...(1)

It crosses the x-axis at (5,0). So put x=5 and y=0 to find the value of a.

$0=a|5-2|+3$

$-3=3a$

$-1=a$

Put a=-1 in (1).

$y=(-1)|x-2|+3$

$y=-|x-2|+3$

Now, put y=0, to find the equation for this absolute value function when y=0.

$0=-|x-2|+3$

Therefore, the correct option is D.

4 0

3 years ago

Read 2 more answers

What is the best estimate for the sum of 3/4 and 1/12

TEA [102]

Well first you would find a common denominator which would be 1w and then since you multiplied 4 by 3 to get to 12 you multiply 3 by 3 which is 9. So then you would have 9/12 + 1/12 which = 10/12

3 0

2 years ago

Can someone help me please .

Ymorist [56]

Answer:

D

Step-by-step explanation:

The angle CDG equals 90 degrees and the angle GDE also equals 90 degrees. Supplementary angles are angles that add up to be 180 degrees.

CDG + GDE = 180 degrees

6 0

3 years ago