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Scrat [10]
2 years ago
5

F(x)=x^2-12x+20 a. f(0) = ? b. f(2) = ? c. f(x) = 0,x = ? d. f(x)= 9,x = ?

Mathematics
1 answer:
bekas [8.4K]2 years ago
5 0

Answer:

c . f(x)=0,x=????????????

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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7 0
3 years ago
Donny's charge account statement showed a previous balance of $765.98, a finance charge of $7.50, new purchases of $97.50 and $3
nataly862011 [7]
I think the answer is 345.75 

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3 years ago
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The graph of an absolute value function has a vertex of (2,3) and crosses the x-axis at (−1,0) and (5,0). What is the equation f
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Answer:

Option D.

Step-by-step explanation:

The vertex form of an absolute function is

y=a|x-h|+k

where, a is a constant, (h,k) is vertex.

It is given that, vertex of an absolute function is (2,3). So, h=2 and k=3.

y=a|x-2|+3   ...(1)

It crosses the x-axis at (5,0). So put x=5 and y=0 to find the value of a.

0=a|5-2|+3

-3=3a

-1=a

Put a=-1 in (1).

y=(-1)|x-2|+3

y=-|x-2|+3

Now, put y=0, to find the equation for this absolute value function when y=0.

0=-|x-2|+3

Therefore, the correct option is D.

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Can someone help me please .
Ymorist [56]

Answer:

D

Step-by-step explanation:

The angle CDG equals 90 degrees and the angle GDE also equals 90 degrees. Supplementary angles are angles that add up to be 180 degrees.

CDG + GDE = 180 degrees

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