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kati45 [8]
1 year ago
13

Why is it necessary to collimate the light source before using the prism to disperse the light?.

Physics
1 answer:
Sergeu [11.5K]1 year ago
5 0

The reason to collimate the light source before utilizing the prism is that if white light enters the prism at various angles, some blue light will exit the prism at the same angle.

Prisms' Dispersion of Light. When light source travels through a triangular prism, these hues are frequently seen. The prism separates the white light source divided into its individual colors, which are red, orange, yellow, green, blue, and violet. Dispersion is the process through which visible light is divided into its various colors.

Since blue light has a shorter wavelength than red light and refracts more than the latter, it is bent more when white light enters a prism than red light.

Learn more about light source here

brainly.com/question/14459326

#SPJ4

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bagirrra123 [75]

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

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3 years ago
2. Which of the following wavelength properties would require a stopwatch to measure?
katovenus [111]

Answer:

<u><em>A. wavelength</em></u>

Explanation:

The others are about sound and how high it is. That has nothing to do with time.

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7 0
3 years ago
A bicycle tire is spinning counterclockwise at 2.70 rad/s. During a time period At 1.90 s, the tire is stopped and spun in the o
Naddik [55]

Answer:

a) -5.40 rad/s

b) -2.842 rad/s²

Explanation:

The direction is important in dealing with such questions. Clockwise is considered negative and counterclockwise is considered positive

a) Δω = final angular velocity - initial angular velocity

          = -2.70 rad/s - 2.70 rad/s

          = -5.40 rad/s

b) ∝ = Δω/Δt = (-5.40 rad/s)/1.90s = -2.842 rad/s²

7 0
4 years ago
A hockey puck slides across the ice with an initial velocity of 7.3 m/s .It has a decleration of 1.1 m/s and is traveling toward
sashaice [31]

Answer:

t = 6.63 s

Explanation:

Given that,

Initial velocity of the puck, u = 7.3 m/s

Deacceleration of the puck, a = -1.1 m/s²

Distance traveled, d = 5 m

We need to find the time the goalie have to stop the puck. Using equation of motion.

v = u +at

v = 0 (stops)

So,

u=-at\\\\t=\dfrac{u}{-a}\\\\t=\dfrac{7.3}{-(-1.1)}\\\\t=6.63\ s

So, the required time is 6.63 seconds.

6 0
3 years ago
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