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kati45 [8]
1 year ago
13

Why is it necessary to collimate the light source before using the prism to disperse the light?.

Physics
1 answer:
Sergeu [11.5K]1 year ago
5 0

The reason to collimate the light source before utilizing the prism is that if white light enters the prism at various angles, some blue light will exit the prism at the same angle.

Prisms' Dispersion of Light. When light source travels through a triangular prism, these hues are frequently seen. The prism separates the white light source divided into its individual colors, which are red, orange, yellow, green, blue, and violet. Dispersion is the process through which visible light is divided into its various colors.

Since blue light has a shorter wavelength than red light and refracts more than the latter, it is bent more when white light enters a prism than red light.

Learn more about light source here

brainly.com/question/14459326

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ahrayia [7]

Work is equal to the force applied times the displacement. Since you pull the wagon at constant speed this means that there is no acceleration on the wagon as it does not change speed. F=ma. Since a=0, F=0. Therefore no work has been done in this situation

3 0
3 years ago
Question 7<br> (01.01 MC)<br> What is the difference between a hypothesis and a theory?
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A hypothermia is like an idea and a theory is something you think
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3 years ago
an object of mass m is rotating about a fixed axis with angular momentum l. its moment of inertia about this axis is i. what is
Tems11 [23]

The Kinetic energy would be 1/2IL².

<h3>What is Rotational Kinetic energy ?</h3>

  • Rotational energy also known as angular kinetic energy is defined as: The kinetic energy due to the rotation of an object and is part of its total kinetic energy. Rotational kinetic energy is directly proportional to the rotational inertia and the square of the magnitude of the angular velocity.

As we know linear Kinetic energy = 1/2mv²

 where m= mass and v= velocity.

Similarly rotational kinetic energy is given by = 1/2IL²

 where I- moment of inertia and L=angular momentum.

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8 0
1 year ago
A cube has a drag coefficient of 0.8. what would be the terminal velocity of a sugar cube 1 cm on a side in air (ρ = 1.2 kg/m3)?
kramer
To answer this question, we should know the formula for the terminal velocity. The formula is written below:

v = √(2mg/ρAC)
where
m is the mass
g is 9.81 m/s²
ρ is density
A is area
C is the drag coefficient

Let's determine the mass, m, to be density*volume.
Volume = s³ = (1 cm*1 m/100 cm)³ = 10⁻⁶ m³
m = (1.6×10³ kg/m³)(10⁻⁶ m³) = 1.6×10⁻³ kg
A = (1 cm * 1 m/100 cm)² = 10⁻⁴ m²

v = √(2*1.6×10⁻³ kg*9.81 m/s²/1.6×10³ kg/m³*10⁻⁴ m²*0.8)
<em>v = 0.495 m/s</em>
7 0
3 years ago
Two students, Jenny and Cho, are investigating motion.
IgorLugansk [536]

Answer:

1: a measuring instruments the students should use for time is a stopwatch

2: a measuring instruments the students should use for distance is a measuring tape

Explanation:

pls mark brainliest

8 0
1 year ago
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