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Marysya12 [62]
3 years ago
13

A ball rolls off an 8.0 m high building and strikes the ground 5.0 m away from the base of the building. How fast was the ball r

olling?
Physics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer: horizontal speed is 3.9 m/s

Explanation: when ball starts to drop, its vertical speed v0 is zero.

We can calculate dropping time from s = v0t +0.5gt².

Dropping time t= √(2s/g)= √((2·8.0 m)/9.81 m/s²)= 1.277 s

Because ball travels horizontal distance s= 5.0 m

HorizontalSpeed v = s/t = 5.0 m/1.277s= 3,915 m/s

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Answer:

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b) \delta h=23.162\ cm

Explanation:

Given:

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a)

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we've the density of the water =1000\ kg.m^{-3}

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Now the same pressure is balanced by the mercury column in the other arm of the tube:

\rho_w.g.h_w=\rho_m.g.h_m

1000\times 9.8\times 0.25=13600\times 9.8\times h_m

h_m=0.01838\ m=1.838\ cm

<u>Now the difference in the column is :</u>

\delta h=h_w-h_m

\delta h=25-1.838

\delta h=23.162\ cm

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